COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 23, Problem 113QAP
To determine
(a)
The number of bright fringes that fit inside the central bright spot due to diffraction having
To determine
(b)
The number of bright fringes that fit inside the central bright spot due to diffraction having wavelength of light
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Students have asked these similar questions
2. What is the width of a single slit through which
510-nm orange light passes to form a first diffraction
minimum at an angle of 25.0°?
Suppose a two-slit interference pattern from 610 nm orange light has its first maximum at an angle of 2.42°. This is a double-slit system already in problem formulation.
What is the separation between two slits for the orange light in meters?
The limit to the eye's acuity is actually related to diffraction by the pupil. What is the angle between two just‑resolvable points of light for a 6.25 mm diameter pupil, assuming the average wavelength of 539 nm?
angle between two points of light:
°
Take the result to be the practical limit for the eye. What is the greatest possible distance a car can be from a person if he or she can resolve its two headlights, given they are 1.20 m apart?
greatest distance at which headlights can be distinguished:
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What is the distance between two just‑resolvable points held at an arm's length (0.750 m) from a person's eye?
distance between two points 0.750 m from a person's eye:
Chapter 23 Solutions
COLLEGE PHYSICS
Ch. 23 - Prob. 1QAPCh. 23 - Prob. 2QAPCh. 23 - Prob. 3QAPCh. 23 - Prob. 4QAPCh. 23 - Prob. 5QAPCh. 23 - Prob. 6QAPCh. 23 - Prob. 7QAPCh. 23 - Prob. 8QAPCh. 23 - Prob. 9QAPCh. 23 - Prob. 10QAP
Ch. 23 - Prob. 11QAPCh. 23 - Prob. 12QAPCh. 23 - Prob. 13QAPCh. 23 - Prob. 14QAPCh. 23 - Prob. 15QAPCh. 23 - Prob. 16QAPCh. 23 - Prob. 17QAPCh. 23 - Prob. 18QAPCh. 23 - Prob. 19QAPCh. 23 - Prob. 20QAPCh. 23 - Prob. 21QAPCh. 23 - Prob. 22QAPCh. 23 - Prob. 23QAPCh. 23 - Prob. 24QAPCh. 23 - Prob. 25QAPCh. 23 - Prob. 26QAPCh. 23 - Prob. 27QAPCh. 23 - Prob. 28QAPCh. 23 - Prob. 29QAPCh. 23 - Prob. 30QAPCh. 23 - Prob. 31QAPCh. 23 - Prob. 32QAPCh. 23 - Prob. 33QAPCh. 23 - Prob. 34QAPCh. 23 - Prob. 35QAPCh. 23 - Prob. 36QAPCh. 23 - Prob. 37QAPCh. 23 - Prob. 38QAPCh. 23 - Prob. 39QAPCh. 23 - Prob. 40QAPCh. 23 - Prob. 41QAPCh. 23 - Prob. 42QAPCh. 23 - Prob. 43QAPCh. 23 - Prob. 44QAPCh. 23 - Prob. 45QAPCh. 23 - Prob. 46QAPCh. 23 - Prob. 47QAPCh. 23 - Prob. 48QAPCh. 23 - Prob. 49QAPCh. 23 - Prob. 50QAPCh. 23 - Prob. 51QAPCh. 23 - Prob. 52QAPCh. 23 - Prob. 53QAPCh. 23 - Prob. 54QAPCh. 23 - Prob. 55QAPCh. 23 - Prob. 56QAPCh. 23 - Prob. 57QAPCh. 23 - Prob. 58QAPCh. 23 - Prob. 59QAPCh. 23 - Prob. 60QAPCh. 23 - Prob. 61QAPCh. 23 - Prob. 62QAPCh. 23 - Prob. 63QAPCh. 23 - Prob. 64QAPCh. 23 - Prob. 65QAPCh. 23 - Prob. 66QAPCh. 23 - Prob. 67QAPCh. 23 - Prob. 68QAPCh. 23 - Prob. 69QAPCh. 23 - Prob. 70QAPCh. 23 - Prob. 71QAPCh. 23 - Prob. 72QAPCh. 23 - Prob. 73QAPCh. 23 - Prob. 74QAPCh. 23 - Prob. 75QAPCh. 23 - Prob. 76QAPCh. 23 - Prob. 77QAPCh. 23 - Prob. 78QAPCh. 23 - Prob. 79QAPCh. 23 - Prob. 80QAPCh. 23 - Prob. 81QAPCh. 23 - Prob. 82QAPCh. 23 - Prob. 83QAPCh. 23 - Prob. 84QAPCh. 23 - Prob. 85QAPCh. 23 - Prob. 86QAPCh. 23 - Prob. 87QAPCh. 23 - Prob. 88QAPCh. 23 - Prob. 89QAPCh. 23 - Prob. 90QAPCh. 23 - Prob. 91QAPCh. 23 - Prob. 92QAPCh. 23 - Prob. 93QAPCh. 23 - Prob. 94QAPCh. 23 - Prob. 95QAPCh. 23 - Prob. 96QAPCh. 23 - Prob. 97QAPCh. 23 - Prob. 98QAPCh. 23 - Prob. 99QAPCh. 23 - Prob. 100QAPCh. 23 - Prob. 101QAPCh. 23 - Prob. 102QAPCh. 23 - Prob. 103QAPCh. 23 - Prob. 104QAPCh. 23 - Prob. 105QAPCh. 23 - Prob. 106QAPCh. 23 - Prob. 107QAPCh. 23 - Prob. 108QAPCh. 23 - Prob. 109QAPCh. 23 - Prob. 110QAPCh. 23 - Prob. 111QAPCh. 23 - Prob. 112QAPCh. 23 - Prob. 113QAPCh. 23 - Prob. 114QAP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Light of wavelength 632.8 nm illuminates a single slit, and a diffraction pattern is formed on a screen 1.00 m from the slit. (a) Using the data in the following table, plot relative intensity versus position. Choose an appropriate value for the slit width a and, on the same graph used for the experimental data, plot the theoretical expression for the relative intensity IImax=sin22 where = (a sin )/. (b) What value of a gives the best fit of theory and experiment? Position Relative to Maximum (mm) Relative Intensity 0 1.00 0.8 0.95 1.6 0.80 3.2 0.39 4.8 0.079 6.5 0.003 8.1 0.036 9.7 0.043 11.3 0.013 12.9 0.000 3 14.5 0.012 16.1 0.015 17.7 0.004 4 19.3 0.000 3arrow_forwardMonochromatic coherent light of amplitude E0 and angular frequency passes through three parallel slits, each separated by a distance d from its neighbor. (a) Show that the time-averaged intensity as a function of the angle is I()=Imax[1+2cos(2dsin)]2 (b) Explain how this expression describes both the primary and the secondary maxima. (c) Determine the ratio of the intensities of the primary and secondary maxima. Hint: See Problem 16.arrow_forwardWhat is the separation between two slits for which 610-nm orange light has its first maximum at an angle of 30.0°?arrow_forward
- Many cells are transparent anti colorless. Structures of great interest in biology and medicine can be practically invisible to ordinary microscopy. To indicate the size and shape of cell structures, an interference micro-scope reveals a difference in index of refraction as a shift in interference fringes. The idea is exemplified in the following problem. An air wedge is formed between two glass plates in contact along one edge and slightly separated at the opposite edge as in Figure P37.37. When the plates are illuminated with monochromatic light from above, the reflected light has 85 dark fringes. Calculate the number of dark fringes that appear if water (n = 1.33) replaces the air between the plates.arrow_forwardWhen we studied Youngs double-slit experiment, we mostly ignored the dark fringe pattern produced by diffraction. Use Figure 35.21 to describe situations in which that omission makes sense. Think especially about the single slit used in front of the double slit in Youngs experiment (Fig. 35.9).arrow_forwardProblem 15: If a diffraction grating is illuminated at normal incidence by coherent (laser) light it produces, on a screen parallel to and far away from the slits, its 4th order intensity maximum, at angles of +/-44 degrees, measured from the central intensity maximum. At what angles, theta 5 and theta 6, measured from the central maximum, will, respectively, the 5th order intensity maximum and the 6th order intensity maximum appear? A. Both are unobservable B. theta5 @ +/- 56.47 degrees theta 6 @ +/- 60.26 degrees C. theta5 @ +/- 55 degrees theta 6 @ +/- 66 degrees D. theta5 @ +/- 63.27 degrees theta 6 is unobservable E. theta 6 @ +/- 60.26 degrees Theta 6 is unobservablearrow_forward
- A thin layer of oil (n=1.28) spills onto the surface of a nearby lake (water has n=1.33). It produces maximum reflection for orange ligh ( 580 nm wavelength). Assuming the maximum occurs in the first order, determine the thickness of the oil slick. Note that by "first order" we mean that this is the minimum amount of shifting required for reflection to occur.arrow_forwardWhat is the wavelength of light in nm falling on double slits separated by 1.96 µm if the third-order maximum is at an angle of 65 °? nmarrow_forwardOne day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 3 cm across, and you estimate that the distance from the window shade to the wall is about 3 m. Estimate the average wavelength of the sunlight (in nm).arrow_forward
- Why is it necessary to examine a thin film with a thickness of only a few wavelengths in order to notice interference? What will happen if we go above the limit? Explain.arrow_forwardIn a Young's double-slit interference apparatus, by what factor is the distance between adjacent light and dark fringes changed when the separation between slits is doubled? Explain.arrow_forwardCat’s eyes have pupils that can be modeled as vertical slits. At night, would cats be more successful in resolving (a) headlights on a distant car or (b) vertically separated lights on the mast of a distant boat?arrow_forward
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Diffraction of light animation best to understand class 12 physics; Author: PTAS: Physics Tomorrow Ambition School;https://www.youtube.com/watch?v=aYkd_xSvaxE;License: Standard YouTube License, CC-BY