EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 24, Problem 24.59AP
Interpretation Introduction
Interpretation:
The reason as to why treatment of the
Concept introduction:
Glucose is an organic compound having the molecular formula of
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(d) Draw the structure of the expected product when monosaccharide B undergo
mutarotation upon dissolving in water in the presence of Tollens reagent (AGNO3,
NHẠOH).
он
OH
O.
OH
OH
OH
monosaccharide B
Draw the structure of the expected product when monosaccharide A undergomutarotation upon dissolving in water in the presence of Tollens reagent (AgNO3,NH4OH).
Draw the structure of the expected product when monosaccharide A undergo mutarotation upon dissolving in water in the presence of Tollens reagent (AgNO3, NH4OH).
Chapter 24 Solutions
EBK ORGANIC CHEMISTRY
Ch. 24 - Prob. 24.1PCh. 24 - Prob. 24.2PCh. 24 - Prob. 24.3PCh. 24 - Prob. 24.4PCh. 24 - Prob. 24.5PCh. 24 - Prob. 24.6PCh. 24 - Prob. 24.7PCh. 24 - Prob. 24.8PCh. 24 - Prob. 24.9PCh. 24 - Prob. 24.10P
Ch. 24 - Prob. 24.11PCh. 24 - Prob. 24.12PCh. 24 - Prob. 24.13PCh. 24 - Prob. 24.14PCh. 24 - Prob. 24.15PCh. 24 - Prob. 24.16PCh. 24 - Prob. 24.17PCh. 24 - Prob. 24.18PCh. 24 - Prob. 24.19PCh. 24 - Prob. 24.20PCh. 24 - Prob. 24.21PCh. 24 - Prob. 24.22PCh. 24 - Prob. 24.23PCh. 24 - Prob. 24.24PCh. 24 - Prob. 24.25PCh. 24 - Prob. 24.26PCh. 24 - Prob. 24.27PCh. 24 - Prob. 24.28PCh. 24 - Prob. 24.29PCh. 24 - Prob. 24.30PCh. 24 - Prob. 24.31PCh. 24 - Prob. 24.32PCh. 24 - Prob. 24.33PCh. 24 - Prob. 24.34APCh. 24 - Prob. 24.35APCh. 24 - Prob. 24.36APCh. 24 - Prob. 24.37APCh. 24 - Prob. 24.38APCh. 24 - Prob. 24.39APCh. 24 - Prob. 24.40APCh. 24 - Prob. 24.41APCh. 24 - Prob. 24.42APCh. 24 - Prob. 24.43APCh. 24 - Prob. 24.44APCh. 24 - Prob. 24.45APCh. 24 - Prob. 24.46APCh. 24 - Prob. 24.47APCh. 24 - Prob. 24.49APCh. 24 - Prob. 24.50APCh. 24 - Prob. 24.51APCh. 24 - Prob. 24.52APCh. 24 - Prob. 24.53APCh. 24 - Prob. 24.54APCh. 24 - Prob. 24.55APCh. 24 - Prob. 24.56APCh. 24 - Prob. 24.57APCh. 24 - Prob. 24.58APCh. 24 - Prob. 24.59APCh. 24 - Prob. 24.60APCh. 24 - Prob. 24.61APCh. 24 - Prob. 24.62AP
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- Regarding 4-O- (α-D-psychofuranosyl) -β-D-allopyranose. Please indicate the RIGHT alternative: (a) The disaccharide reacts with CH3OH in an acid medium to form a glycoside that cannot be oxidized with HNO3. (b) It is a reducing disaccharide only in basic medium. (c) In the structure there is only one glycosidic bond that is of the type β 1-O-4 ' (d) The hydrolysis products of this disaccharide do not show mutarrotation. (e) The disaccharide structure contains two six-membered rings.arrow_forwardDraw the structure of: (a) a polysaccharide formed by joining D-mannose units in 1→4-β- glycosidic linkages; (b) a polysaccharide formed by joining D-glucose units in 1→6-α- glycosidic linkages. The polysaccharide in (b) is dextran, a component of dental plaque.arrow_forward4. Identify the component monosaccharides of each of the following compounds and describe the type of glycosidic linkage in each. Но он Но OH HO он Но- Но- (a) OH (c) CH,OHO. (b) CH2OHO Lon OH HO H ČHOH H OH ÓH ОНarrow_forward
- Draw the structure of a carbohydrate with four b-D-glucopyranosyl units connected by b(1®4) glycosidic linkages, with the second unit being connected via an a(1®6) glycosidic linkage by a side chain having two a-D-galactopyranosyl units connected by an a(1®4) glycosidic linkage.arrow_forwardDraw the structures (using chair conformations of pyranoses) of the following disaccharides.(a) 4-O-(a-d-glucopyranosyl)-d-galactopyranose(arrow_forwarddoes structure E represent fructofuranose? explainarrow_forward
- #6 B D F INSTRUCTIONS: Characterize the members of each of the following pairs of structures as enantiomers, diastereomers or neither enantiomers nor diastereomers.arrow_forwardThe anticoagulant heparin is a polysaccharide that contains alternating residues of -D- glucuronic acid-6- sulfate and N-sulfo-D-glucosamine-6sulfate connected by (1 B 4)- glycosidic linkages. Draw a part of heparin that shows one each of the two residues.arrow_forwardd-(-)-Erythrose has the formula HOCH2¬CH(OH)¬CH(OH)¬CHO, and the d in its name implies that it can be degraded to d-(+)-glyceraldehyde. The (-) in its name implies that d-(-)-erythrose is optically active (levorotatory). When d-(-)-erythrose is reduced (using H2 and a nickel catalyst), it gives an optically inactive product of formula HOCH2¬CH(OH)¬CH(OH)¬CH2OH. Knowing the absolute configuration of d-(+)-glyceraldehyde (Section 5-14), determine the absolute configuration of d-(-)-erythrose.arrow_forward
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