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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The formula of Kynamro is C230H305N67O122P19S19Na19. How many nucleotides are present in one molecule of Kynamro?

Interpretation Introduction

Interpretation:

The number of nucelotide in one molecule of Kynamro (C230H305N67O122P19S19Na19) has to be identified.

Concept introduction: Nucleotide is made up of three parts: a phosphate group, a ribose sugar and a nitrogenous base.The four nitrogenous base in DNA are Adenine, guanine, cytosine and thymine.

The drug call ‘Kynamro’ targets the mRNA for protein involved in a rare condition that lead to very high level of cholestreol called homozygous familial hypercholestreolemia.

Kynamro uses the backbone that contain phosphorothioate group in which oxygen attached to phosphorous is replaced by sulphur atom.

Explanation

Kynamro has phosphorothioate group as a backbone in which oxygen attached to phosphorous is replaced by sulphur atom.

Total number of phosphrous atom present in one molecule of Kynamro is 19 which indicates that there are 19 phosphorothioate linkage in a group , which implies that there are 20 nucleotide in one molecule of Kynamro

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