BIO 1406/07 W/CONNECT/LM NEW >IC<
16th Edition
ISBN: 9781260075762
Author: Raven
Publisher: MCG CUSTOM
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Textbook Question
Chapter 25, Problem 10U
Independently derived mutations of the CTC gene in plants
a. suggests bilateral floral symmetry among all plant is homologous.
b. establishes that radial floral symmetry is preferred by pollinators.
c. establishes that radial floral symmetry is derived for all plants.
d. None of the choices are correct.
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A. The genes CLV3, CLV1/2 and WUS are involved in maintaining the size of shoot apical meristem. Diagram the interactions among these gene products, using ‘—>’ for positive interactions (i.e. activation) and ‘ —|’ for negative interactions (i.e. repression).
B. What phenotype would you expect for a double mutant clv3 wus? And why?
Can you solve all the parts to this question please
a) What is the role of the LEAFY gene in floral development?
(b) What is the phenotype of the leafy mutant?
(c) Most of the ABC program genes are directly regulated by the transcription factor LEAFY (LFY). Still, LFY is expressed broadly throughout the floral meristem when the discrete A, B, and C domains are established. Discuss how this single broadly expressed transcription factor can generate distinct domains of ABC gene expression. Feel free to use diagrams.
Can you answer both questions please
(b) Based on the ABC model, what would be the predicted phenotype of a double AB mutant?
(c) In developing flowers of dioecious Spinach and Thalictrum, stamens are not developed in female flowers,
and carpels are not developed in male flowers. What is the simplest model of ABC class gene expression that
might explain this?
Whorl 1
Whorl 2
Whorl 3
Whorl 4
Wild type
sepals
petals
stamens
carpels
A class gene Carpels
stamens stamen carpel
mutants
B class gene
Sepal Sepal carpel carpel
C class gene Sepal petal petal sepal
mutants
mutants
Chapter 25 Solutions
BIO 1406/07 W/CONNECT/LM NEW >IC<
Ch. 25 - Heterochrony is a. the alteration of the spatial...Ch. 25 - Vast differences in the phenotypes of organisms as...Ch. 25 - Homoplastic structures a can Involve convergence...Ch. 25 - Hox genes are a. found in both plants and animals....Ch. 25 - The Brachyury and Thx5 in vertebrates and the Ap3...Ch. 25 - Which of the following statements about Pax6 is...Ch. 25 - Which of the following statements about TbxS is...Ch. 25 - Prob. 8UCh. 25 - Transcription factors are a. genes. b. sequences...Ch. 25 - Independently derived mutations of the CTC gene in...
Ch. 25 - Prob. 1ACh. 25 - Prob. 2ACh. 25 - The Eda allele that causes reduced armor...Ch. 25 - Prob. 4ACh. 25 - The paired-like homeodomain transcription factor 1...Ch. 25 - From the chapter on evolution of development it...Ch. 25 - Phenotypic diversity among major groups of...Ch. 25 - Critique the argument that eyes have multiple...Ch. 25 - Prob. 5SCh. 25 - Having read all of this chapter return to the clam...
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- Can you answer both questions please (b) Based on the ABC model, what would be the predicted phenotype of a double AB mutant? (c) In developing flowers of dioecious Spinach and Thalictrum, stamens are not developed in female flowers, and carpels are not developed in male flowers. What is the simplest model of ABC class gene expression that might explain this?arrow_forward. In the plant Arabidopsis thaliana, a geneticist is interested in the development of trichomes (small projections). A large screen turns up two mutant plants (A and B) that have no trichomes, and these mutants seem to be potentially useful in studying trichome development. (If they were determined by single-gene mutations, then finding the normal and abnormal functions of these genes would be instructive.) Each plant is crossed with wild type; in both cases, the next generation (F1) had normal trichomes. When F1 plants were selfed, the resulting F2’s were as follows: F2 from mutant A: 602 normal; 198 no trichomes F2 from mutant B: 267 normal; 93 no trichomesa. What do these results show? Include proposed genotypes of all plants in your answer. b. Under your explanation to part a, is it possible to confidently predict the F1 from crossing the original mutant A with the original mutant B?arrow_forwardCan you answer part a-c if its true or false a) the AP3 and PI show auto- and cross-regulatory interactions, as well as they form obligate heterodimers to carry out the B class gene function. Therefore, if there is no PI expression, AP3 expression alone is not sufficient for establishing the petal and stamen identities. b) Angiosperm is a group of plants whose seeds are borne within a mature ovary (fruit). c) The organ in different organisms under every variety of forms and functions due to evolutionary development from the same or a corresponding part in a common ancestor is homologous.arrow_forward
- Which of the following BEST states genome editing in plants? A. transform large DNA constructs by suppression and activation B. insert a functional cis-regulatory element in the natural genes transgene vector C. assemble and synthesize large DNA molecules in a single transgene vector D. deletion, mutation, or integration of the gene of interest depending on the target traitarrow_forwardYou are a developmental geneticist studying flowering time variation in Arabidopsis. You perform a mutagenesis screen to identify mutants in the photoperiod pathway. Given what you know about photoperiodism in Arabidopsis, what phenotype are you looking for and under what photoperiodic conditions would you perform the experiment? delayed flowering in long days delayed flowering in short days same flowering in short days early flowering in short days same flowering in long days early flowering in long daysarrow_forward1a.Discovery of genes controlling Gibberellic Acid (GA) synthesis and perception became very important during the Green Revolution, and remain important today. Why? Select one: a. Mutants with reduced GA levels are dwarfs. Many dwarf plants were important for the Green Revolution because the shorter plants can invest more energy into economically important parts like seeds (instead of stem length). b. Mutants with reduced GA levels are more resistant to herbivore damage (like caterpillars), increasing plant yields. c. Mutants with reduced GA levels allowed farmers to control fruit ripening more accurately. d. Mutants with reduced GA levels have increased photosynthesis 1b. What features are important for overall plant form? Select one: a. Iterative development and capillary action b. Iterative development and apical dominance c. Apical dominance and stomatal conductance d. Phyllotaxis and capillary actionarrow_forward
- You are a developmental geneticist studying flowering time variation in Arabidopsis. You perform a mutagenesis screen to identify mutants in the photoperiod pathway. You conduct the screen and find two different plants that show the same mutant phenotype. You then use a complementation test. What is the predicted outcome of this test if both phenotypes are caused by mutations in separate genes? recover the wild type phenotype overexpress the gene O recover the mutant phenotypearrow_forwardExplain how (a) the absence of class B gene expression produces the flower structures seen in class B mutants (see Figure 22.15c) and (b) the absence of class C gene expression produces the structures seen in class C mutants (see Figure 22.15d).arrow_forwardDescribe in detail a molecular mechanism that could explain how two groups of genetically identical plants differ in their gene expressions to produce different flower colors?arrow_forward
- If Gus is present in the Arabidopsis Thaliana what is it indicating? I know its to show gene expression, but what is the importance of that? I hope this makes sensearrow_forwardA close relative of this flower has very large sepals compared to this one. Apply what you know about morphogenesis in plants to make a hypothesis of how A close relative of this flower has very large sepals compared to this one. Apply what you know about morphogenesis in plants to make a hypothesis of how gene expression might differ in the relative compared to this plant. Be sure to relate it to the figure above. in the relative compared to this plant. Be sure to relate it to the figure above.arrow_forwardIn Corn, Male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of corn plants(i.e. the tassol) unable to produce fertile pollen; the female parts. However, remain receptive to pollination by pollen from male fertile corn plants, however the presence of a nuclear fertility restore gene F restores fertility to make sterile lines. b. Explain the phenotype of the offspring.arrow_forward
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