Structure of optically inactive triglyceride need to be drawn from the given glycerol and one equivalent of palmitic acid and two equivalents of oleic acid obtained from hydrolysis. Concept introduction: Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis. From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol. To draw : the structure of optically inactive triglyceride from the given problem statement.

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Answer 1

Question

Chapter 26, Problem 46PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol and one equivalent of palmitic acid and two equivalents of oleic acid obtained from hydrolysis.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

To draw: the structure of optically inactive triglyceride from the given problem statement.

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Answer 2

Question

Chapter 26, Problem 46PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol and one equivalent of palmitic acid and two equivalents of oleic acid obtained from hydrolysis.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

To draw: the structure of optically inactive triglyceride from the given problem statement.

Expert Solution & Answer

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Answer 3

Question

Chapter 26, Problem 46PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol and one equivalent of palmitic acid and two equivalents of oleic acid obtained from hydrolysis.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

To draw: the structure of optically inactive triglyceride from the given problem statement.

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Answer 4

Question

Chapter 26, Problem 46PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol and one equivalent of palmitic acid and two equivalents of oleic acid obtained from hydrolysis.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

To draw: the structure of optically inactive triglyceride from the given problem statement.

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Answer 5

Chapter 26, Problem 46PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol and one equivalent of palmitic acid and two equivalents of oleic acid obtained from hydrolysis.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

To draw: the structure of optically inactive triglyceride from the given problem statement.

Answer 6

Chapter 26, Problem 46PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol and one equivalent of palmitic acid and two equivalents of oleic acid obtained from hydrolysis.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

To draw: the structure of optically inactive triglyceride from the given problem statement.

Answer 7

Chapter 26, Problem 46PP

Interpretation Introduction

Interpretation:

Structure of optically inactive triglyceride need to be drawn from the given glycerol and one equivalent of palmitic acid and two equivalents of oleic acid obtained from hydrolysis.

Concept introduction:

Esterification is a process in which the carboxylic acid and an alcohol react to form a ester bond. This can take place in presence of acid or base. The bond is formed due to loss of water molecule when the condensation reaction takes place. Simply to say esterification is the reverse process of hydrolysis.

From the above scheme we can find out the starting triglyceride considering the fatty acid and glycerol.

To draw: the structure of optically inactive triglyceride from the given problem statement.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 26.2 - Prob. 1CC Ch. 26.2 - Prob. 2CC Ch. 26.3 - Prob. 1LTS Ch. 26.3 - Prob. 3PTS Ch. 26.3 - Prob. 4ATS Ch. 26.3 - Prob. 5ATS Ch. 26.3 - Prob. 6ATS Ch. 26.4 - Prob. 7CC Ch. 26.4 - Prob. 8CC Ch. 26.4 - Prob. 2LTS

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Chapter 26 Solutions