Trace out the pathway that terminates with a stable nucleus for each of the radioactive decay.
Explanation of Solution
Calculation:
A. Thorium Series: A = 4n
There is another path from Bi-212
B. Uranium Series: A = 4n+2
C. Actinium Series: A = 4n+3
The above then breaks into two pathways, a and b, which eventually converge
At this point the chain diverges
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Chapter 27 Solutions
College Physics Volume 2
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