   Chapter 10, Problem 48P ### University Physics Volume 3

17th Edition
William Moebs + 1 other
ISBN: 9781938168185

#### Solutions ### University Physics Volume 3

17th Edition
William Moebs + 1 other
ISBN: 9781938168185
Textbook Problem

# Write a nuclear β − decay reaction that produces the 90Y nucleus. (Hint: The parent nuclide is a major waste product of reactors and has chemistry similar to calcium, so that it is concentrated in bones if ingested.)

To determine

Nuclear β- decay reaction that generates the 90Y.

Explanation

Introduction:

A β- particle is a high-speed electron when a radioactive nuclide like 90Sr undergoes β- decay, a neutron located inside its nucleus is converted into a proton. And at the same time, -10β particle and an electron anti-neutrino, υe- are emitted. It has no electrons to balance the proton having a positive charge.

Beta particle (β-) is a particle similar to that of the electron. Daughter nuclide after its emission has 1 proton more than the parent nuclide. After the emission of daughter nuclide, it has an atomic number more than parent nuclide by 1. But they do not have any difference in their atomic mass.

Equation of nuclide after beta decay is

ZAXZ+1AY+-10β+υe- .......................... (1)

Here,

A= Atomic mass, Z= Atomic number, Y= Daughter nuclide element, X= Parent nuclide element,

υe- = Electron's anti-neutrino.

The element Y (Yttrium's) atomic mass is 90. Before the β- decay to 3990Y, the atomic number of parent nuclide is given by 391=38.

The atomic mass of parent and daughter nuclei remains the same.

The atomic mass of parent nuclide is,

90+0=90

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