BuyFindarrow_forward

Contemporary Mathematics for Busin...

8th Edition
Robert Brechner + 1 other
ISBN: 9781305585447

Solutions

Chapter
Section
BuyFindarrow_forward

Contemporary Mathematics for Busin...

8th Edition
Robert Brechner + 1 other
ISBN: 9781305585447
Textbook Problem

Reduce the following fractions to lowest terms.

a. 270 810

b. 175 232

(a)

To determine

To calculate: The fraction 270810 in the lowest terms.

Explanation

Given Information:

The provided fraction is 270810.

Formula used:

Greatest common divisor method:

Step 1: Divide the denominator by the numerator of the fraction.

Step 2: Now, check the remainder,

(a): If remainder is 0 then stop, thus divisor is the greatest common divisor.

(b): If remainder is 1 then stop, there is no greatest common divisor and thus the fraction is already in its lowest term.

(c): If it is any other number than 0 and 1 then divide the divisor by the remainder.

Step 3: Repeat step 2, if required.

Step 4: Now, divide the numerator and denominator of fraction by the obtained greatest common divisor to get the lowest term.

Calculation:

Consider the fraction 270810.

Divide the denominator 810 by the numerator 270

(b)

To determine

To calculate: The fraction 175232 in the lowest terms.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started
Sect-2.I P-5RESect-2.I P-6RESect-2.I P-7RESect-2.I P-8RESect-2.I P-9RESect-2.I P-10RESect-2.I P-11RESect-2.I P-12RESect-2.I P-13RESect-2.I P-14RESect-2.I P-15RESect-2.I P-16RESect-2.I P-17RESect-2.I P-18RESect-2.I P-19RESect-2.I P-20RESect-2.I P-21RESect-2.I P-22RESect-2.I P-23RESect-2.I P-24RESect-2.I P-25RESect-2.I P-26RESect-2.I P-27RESect-2.I P-28RESect-2.I P-29RESect-2.I P-30RESect-2.I P-31RESect-2.I P-32RESect-2.I P-33RESect-2.I P-34RESect-2.I P-35RESect-2.I P-36RESect-2.I P-37RESect-2.I P-38RESect-2.I P-39RESect-2.I P-40RESect-2.I P-41RESect-2.I P-42RESect-2.I P-43RESect-2.I P-44RESect-2.II P-7TIESect-2.II P-8TIESect-2.II P-9TIESect-2.II P-10TIESect-2.II P-11TIESect-2.II P-12TIESect-2.II P-13TIESect-2.II P-1RESect-2.II P-2RESect-2.II P-3RESect-2.II P-4RESect-2.II P-5RESect-2.II P-6RESect-2.II P-7RESect-2.II P-8RESect-2.II P-9RESect-2.II P-10RESect-2.II P-11RESect-2.II P-12RESect-2.II P-13RESect-2.II P-14RESect-2.II P-15RESect-2.II P-16RESect-2.II P-17RESect-2.II P-18RESect-2.II P-19RESect-2.II P-20RESect-2.II P-21RESect-2.II P-22RESect-2.II P-23RESect-2.II P-24RESect-2.II P-25RESect-2.II P-26RESect-2.II P-27RESect-2.II P-28RESect-2.II P-29RESect-2.II P-30RESect-2.II P-31RESect-2.II P-32RESect-2.II P-33RESect-2.II P-34RESect-2.II P-35RESect-2.III P-14TIESect-2.III P-15TIESect-2.III P-16TIESect-2.III P-1RESect-2.III P-2RESect-2.III P-3RESect-2.III P-4RESect-2.III P-5RESect-2.III P-6RESect-2.III P-7RESect-2.III P-8RESect-2.III P-9RESect-2.III P-10RESect-2.III P-11RESect-2.III P-12RESect-2.III P-13RESect-2.III P-14RESect-2.III P-15RESect-2.III P-16RESect-2.III P-17RESect-2.III P-18RESect-2.III P-19RESect-2.III P-20RESect-2.III P-21RESect-2.III P-22RESect-2.III P-23RESect-2.III P-24RESect-2.III P-25RESect-2.III P-26RESect-2.III P-27RESect-2.III P-28RESect-2.III P-29RESect-2.III P-30RESect-2.III P-31RESect-2.III P-32RESect-2.III P-33RESect-2.III P-34RESect-2.III P-35RESect-2.III P-36RESect-2.III P-37RESect-2.III P-38RESect-2.III P-39RESect-2.III P-40RECh-2 P-1CRCh-2 P-2CRCh-2 P-3CRCh-2 P-4CRCh-2 P-5CRCh-2 P-6CRCh-2 P-7CRCh-2 P-8CRCh-2 P-9CRCh-2 P-10CRCh-2 P-11CRCh-2 P-12CRCh-2 P-13CRCh-2 P-14CRCh-2 P-1ATCh-2 P-2ATCh-2 P-3ATCh-2 P-4ATCh-2 P-5ATCh-2 P-6ATCh-2 P-7ATCh-2 P-8ATCh-2 P-9ATCh-2 P-10ATCh-2 P-11ATCh-2 P-12ATCh-2 P-13ATCh-2 P-14ATCh-2 P-15ATCh-2 P-16ATCh-2 P-17ATCh-2 P-18ATCh-2 P-19ATCh-2 P-20ATCh-2 P-21ATCh-2 P-22ATCh-2 P-23ATCh-2 P-24ATCh-2 P-25ATCh-2 P-26ATCh-2 P-27ATCh-2 P-28ATCh-2 P-29ATCh-2 P-30ATCh-2 P-31AT

Additional Math Solutions

Find more solutions based on key concepts

Show solutions add

Expand each expression in Exercises 122. (y+3)(y+4)

Finite Mathematics and Applied Calculus (MindTap Course List)

Find all solutions of the equation. 24. z2+12z+14=0

Single Variable Calculus: Early Transcendentals, Volume I

In Exercises 85-88, determine whether the statement is true or false. If it is true, explain why it is true. If...

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

True or False: These lines are skew:

Study Guide for Stewart's Multivariable Calculus, 8th

What is the partial fraction form of ?

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th