Custom eBook for Organic Chemistry
Custom eBook for Organic Chemistry
2nd Edition
ISBN: 9798214171104
Author: Straumanis
Publisher: Cengage Custom
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Chapter 3, Problem 16CTQ

Now consider the fully formed molecule on the right side of Figure 3.7.
a. Draw a Lewis structure of this molecule.
b. Identify orbital representations of the two π bonds and three σ bonds in Figure 3.7, andmatch these with representations of bonds on the Lewis structure you just drew.

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1) For each condensed or skeletal structure below: A. Draw a complete Lewis structure. Note: show all non-bonding electron pairs. B. Indicate the hybridization of all C, O, and N atoms in each of the molecules. C. Label each of the indicated bonds (marked by an arrow) as either a sigma or pi bond. (Note: Remember, e.g. that a double bond is made up of both a o and a π bond). Also indicate which orbitals overlap to form the bond (e.g., Ols-2sp3). D. For atoms having lone pairs in the molecules below, indicate in which orbitals the lone pairs are located. E. Which of the bonds indicated by arrows is shorter? a) c) H CH3 C=CHC=C-CH g) (CH3)3CCN CH3 CH₂CH=CHCECH b) d) CH3 Lo LOH f) CH₂CH(CH3)SH h) (CH3)2CH(CH₂)3Br
Q/ For the Lewis structure below…• Draw all of its important resonance structures. Show all charges and lone pair electrons. Use curved arrows to show the flow of electrons leading to each successive structure.• Draw the resonance hybrid. Label the average bond order and average charges
a) Draw the Lewis structure for the molecule on the left (labeled as Molecule A above). Draw the Lewis structure which has minimum formal charges.  b) Draw the correct Lewis structure for the molecule on the right (labeled as Molecule B above). Draw the Lewis structure which has minimum formal charges. c) Select the three TRUE statements from those provided below. The molecule on the right (Molecule B) is planar (all atoms lie within the same plane). The molecule on the left (Molecule A) is planar (all atoms lie within the same plane). The molecule on the right (Molecule B) has polar bonds. The molecule on the left (Molecule A) has polar bonds. We can distinguish between the two molecules (Molecule A and Molecule B) based upon their dipole moment.
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