LP formulation:

The following example of LP is to show that it has more than one optimal solution.

It also contains nondegenerate basic feasible solution and there is non-basic variable in row 0 with a zero coefficient.

max z=6x₁+4x₂

Such that

x1+2x2≤16

3x1+2x2≤24

x1,x2≥0

Solving by the simplex method, the initial table is,

c_j 6 4 0 0 Ratio
c_j x_j B_j x₁ x₂ S₁ S₂ (Bix1)
0 S₁ 16 1 2 1 0 16
0 S₂ 24 3 2 0 1 8
zj−cj -6 -4 0 0

Here x₁ will enter as it is the greatest negative value

Expert Solution & Answer

Chapter 3 Solutions

Operations Research : Applications and Algorithms

Ch. 3.1 - Prob. 1P Ch. 3.1 - Prob. 2P Ch. 3.1 - Prob. 3P Ch. 3.1 - Prob. 4P Ch. 3.1 - Prob. 5P Ch. 3.2 - Prob. 1P Ch. 3.2 - Prob. 2P Ch. 3.2 - Prob. 3P Ch. 3.2 - Prob. 4P Ch. 3.2 - Prob. 5P

Ch. 3.2 - Prob. 6P Ch. 3.3 - Prob. 1P Ch. 3.3 - Prob. 2P Ch. 3.3 - Prob. 3P Ch. 3.3 - Prob. 4P Ch. 3.3 - Prob. 5P Ch. 3.3 - Prob. 6P Ch. 3.3 - Prob. 7P Ch. 3.3 - Prob. 8P Ch. 3.3 - Prob. 9P Ch. 3.3 - Prob. 10P Ch. 3.4 - Prob. 1P Ch. 3.4 - Prob. 2P Ch. 3.4 - Prob. 3P Ch. 3.4 - Prob. 4P Ch. 3.5 - Prob. 1P Ch. 3.5 - Prob. 2P Ch. 3.5 - Prob. 3P Ch. 3.5 - Prob. 4P Ch. 3.5 - Prob. 5P Ch. 3.5 - Prob. 6P Ch. 3.5 - Prob. 7P Ch. 3.6 - Prob. 1P Ch. 3.6 - Prob. 2P Ch. 3.6 - Prob. 3P Ch. 3.6 - Prob. 4P Ch. 3.6 - Prob. 5P Ch. 3.7 - Prob. 1P Ch. 3.8 - Prob. 1P Ch. 3.8 - Prob. 2P Ch. 3.8 - Prob. 3P Ch. 3.8 - Prob. 4P Ch. 3.8 - Prob. 5P Ch. 3.8 - Prob. 6P Ch. 3.8 - Prob. 7P Ch. 3.8 - Prob. 8P Ch. 3.8 - Prob. 9P Ch. 3.8 - Prob. 10P Ch. 3.8 - Prob. 11P Ch. 3.8 - Prob. 12P Ch. 3.8 - Prob. 13P Ch. 3.8 - Prob. 14P Ch. 3.9 - Prob. 1P Ch. 3.9 - Prob. 2P Ch. 3.9 - Prob. 3P Ch. 3.9 - Prob. 4P Ch. 3.9 - Prob. 5P Ch. 3.9 - Prob. 6P Ch. 3.9 - Prob. 7P Ch. 3.9 - Prob. 8P Ch. 3.9 - Prob. 9P Ch. 3.9 - Prob. 10P Ch. 3.9 - Prob. 11P Ch. 3.9 - Prob. 12P Ch. 3.9 - Prob. 13P Ch. 3.9 - Prob. 14P Ch. 3.10 - Prob. 1P Ch. 3.10 - Prob. 2P Ch. 3.10 - Prob. 3P Ch. 3.10 - Prob. 4P Ch. 3.10 - Prob. 5P Ch. 3.10 - Prob. 6P Ch. 3.10 - Prob. 7P Ch. 3.10 - Prob. 8P Ch. 3.10 - Prob. 9P Ch. 3.11 - Prob. 1P Ch. 3.11 - Show that Finco’s objective function may also be...Ch. 3.11 - Prob. 3P Ch. 3.11 - Prob. 4P Ch. 3.11 - Prob. 7P Ch. 3.11 - Prob. 8P Ch. 3.11 - Prob. 9P Ch. 3.12 - Prob. 2P Ch. 3.12 - Prob. 3P Ch. 3.12 - Prob. 4P Ch. 3 - Prob. 1RP Ch. 3 - Prob. 2RP Ch. 3 - Prob. 3RP Ch. 3 - Prob. 4RP Ch. 3 - Prob. 5RP Ch. 3 - Prob. 6RP Ch. 3 - Prob. 7RP Ch. 3 - Prob. 8RP Ch. 3 - Prob. 9RP Ch. 3 - Prob. 10RP Ch. 3 - Prob. 11RP Ch. 3 - Prob. 12RP Ch. 3 - Prob. 13RP Ch. 3 - Prob. 14RP Ch. 3 - Prob. 15RP Ch. 3 - Prob. 16RP Ch. 3 - Prob. 17RP Ch. 3 - Prob. 18RP Ch. 3 - Prob. 19RP Ch. 3 - Prob. 20RP Ch. 3 - Prob. 21RP Ch. 3 - Prob. 22RP Ch. 3 - Prob. 23RP Ch. 3 - Prob. 24RP Ch. 3 - Prob. 25RP Ch. 3 - Prob. 26RP Ch. 3 - Prob. 27RP Ch. 3 - Prob. 28RP Ch. 3 - Prob. 29RP Ch. 3 - Prob. 30RP Ch. 3 - Graphically find all solutions to the following...Ch. 3 - Prob. 32RP Ch. 3 - Prob. 33RP Ch. 3 - Prob. 34RP Ch. 3 - Prob. 35RP Ch. 3 - Prob. 36RP Ch. 3 - Prob. 37RP Ch. 3 - Prob. 38RP Ch. 3 - Prob. 39RP Ch. 3 - Prob. 40RP Ch. 3 - Prob. 41RP Ch. 3 - Prob. 42RP Ch. 3 - Prob. 43RP Ch. 3 - Prob. 44RP Ch. 3 - Prob. 45RP Ch. 3 - Prob. 46RP Ch. 3 - Prob. 47RP Ch. 3 - Prob. 48RP Ch. 3 - Prob. 49RP Ch. 3 - Prob. 50RP Ch. 3 - Prob. 51RP Ch. 3 - Prob. 52RP Ch. 3 - Prob. 53RP Ch. 3 - Prob. 54RP Ch. 3 - Prob. 56RP Ch. 3 - Prob. 57RP Ch. 3 - Prob. 58RP Ch. 3 - Prob. 59RP Ch. 3 - Prob. 60RP Ch. 3 - Prob. 61RP Ch. 3 - Prob. 62RP Ch. 3 - Prob. 63RP

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		c_j	6	4	0	0	Ratio
c_j	x_j	B_j	x₁	x₂	S₁	S₂	(Bix1)
0	S₁	16	1	2	1	0	16
0	S₂	24	3	2	0	1	8
		zj−cj	-6	-4	0	0