Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 30, Problem 50CP
(a)
To determine
To show: The direction of the electric field is in the correct direction to make the electrons speed up.
(b)
To determine
To show: The average magnetic field over the area enclosed by the orbit must be twice as large as the magnetic field at the circle’s circumference.
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Check out a sample textbook solutionChapter 30 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 30.1 - A circular loop of wire is held in a uniform...Ch. 30.2 - QUICK QUIZ 30.2 In Figure 30.8a, a given applied...Ch. 30.3 - Figure 30.12 (Quick Quiz 30.3) QUICK QUIZ 30.3...Ch. 30.5 - Prob. 30.4QQCh. 30 - A circular loop of wire of radius 12.0 cm is...Ch. 30 - An instrument based on induced emf has been used...Ch. 30 - Scientific work is currently under way to...Ch. 30 - A long solenoid has n = 400 turns per meter and...Ch. 30 - An aluminum ring of radius r1 = 5.00 cm and...Ch. 30 - Prob. 6P
Ch. 30 - A coil formed by wrapping 50 turns of wire in the...Ch. 30 - Prob. 8PCh. 30 - A toroid having a rectangular cross section (a =...Ch. 30 - A small airplane with a wingspan of 14.0 m is...Ch. 30 - A helicopter (Fig. P30.11) has blades of length...Ch. 30 - A 2.00-m length of wire is held in an eastwest...Ch. 30 - A metal rod of mass m slides without friction...Ch. 30 - Prob. 14PCh. 30 - Prob. 15PCh. 30 - Prob. 16PCh. 30 - You are working for a company that manufactures...Ch. 30 - You are working in a laboratory that uses motional...Ch. 30 - You are working in a factory that produces long...Ch. 30 - Prob. 20PCh. 30 - Within the green dashed circle show in Figure...Ch. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Figure P30.24 (page 820) is a graph of the induced...Ch. 30 - The rotating loop in an AC generator is a square...Ch. 30 - In Figure P30.26, a semicircular conductor of...Ch. 30 - Prob. 27PCh. 30 - Prob. 28APCh. 30 - Prob. 29APCh. 30 - Prob. 30APCh. 30 - A circular coil enclosing an area of 100 cm2 is...Ch. 30 - Prob. 32APCh. 30 - A guitars steel string vibrates (see Fig. 30.5)....Ch. 30 - Prob. 34APCh. 30 - A conducting rod of length = 35.0 cm is free to...Ch. 30 - Prob. 36APCh. 30 - Prob. 37APCh. 30 - In Figure P30.38, the rolling axle, 1.50 m long,...Ch. 30 - Figure P30.39 shows a stationary conductor whose...Ch. 30 - Prob. 40APCh. 30 - Figure P30.41 shows a compact, circular coil with...Ch. 30 - Review. In Figure P30.42, a uniform magnetic field...Ch. 30 - An N-turn square coil with side and resistance R...Ch. 30 - A conducting rod of length moves with velocity v...Ch. 30 - A long, straight wire carries a current given by I...Ch. 30 - A rectangular loop of dimensions and w moves with...Ch. 30 - A thin wire = 30.0 cm long is held parallel to...Ch. 30 - Prob. 48CPCh. 30 - Prob. 49CPCh. 30 - Prob. 50CPCh. 30 - Review. The bar of mass m in Figure P30.51 is...
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- Assume the region to the right of a certain plane contains a uniform magnetic field of magnitude 1.00 mT and the field is zero in the region to the left of the plane as shown in Figure P22.71. An electron, originally traveling perpendicular to the boundary plane, passes into the region of the field. (a) Determine the time interval required for the electron to leave the field-filled region, noting that the electrons path is a semicircle. (b) Assuming the maximum depth of penetration into the field is 2.00 cm, find the kinetic energy of the electron.arrow_forwardWhy is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forwardA proton moving in the plane of the page has a kinetic energy of 6.00 MeV. A magnetic field of magnitude H = 1.00 T is directed into the page. The proton enters the magnetic field with its velocity vector at an angle = 45.0 to the linear boundary of' the field as shown in Figure P29.80. (a) Find x, the distance from the point of entry to where the proton will leave the field. (b) Determine . the angle between the boundary and the protons velocity vector as it leaves the field.arrow_forward
- Determine the initial direction of the deflection of charged particles as they enter the magnetic fields as shown in Figure P22.2. Figure P22.2.arrow_forwardA mass spectrometer (Fig. 30.40, page 956) operates with a uniform magnetic field of 20.0 mT and an electric field of 4.00 103 V/m in the velocity selector. What is the radius of the semicircular path of a doubly ionized alpha particle (ma = 6.64 1027 kg)?arrow_forwardA proton moving horizontally enters a region where a uniform magnetic field is directed perpendicular to the proton’s velocity as shown in Figure OQ22.4. After the proton enters the field, does it (a) deflect downward, with its speed remaining constant; (b) deflect upward, moving in a semicircular path with constant speed, and exit the field moving to the left; (c) continue to move in the horizontal direction with constant velocity; (d) move in a circular orbit and become trapped by the field; or (e) deflect out of the plane of the paper? Figure OQ22.4arrow_forward
- Consider an electron rotating in a circular orbit of radius r. Show that the magnitudes of the magnetic dipole moment and the angular momentum L of the electron are related by: = L=e2marrow_forwardWhen the current through a circular loop is 6.0 A, the magnetic field at its center is 2.0104 T. What is the radius of the loop?arrow_forwardCalculate the magnitude of the magnetic field at a point 25.0 cm from a long, thin conductor carrying a current of 2.00 A.arrow_forward
- A wire 2.80 m in length carries a current of 5.00 A in a region where a uniform magnetic field has a magnitude of 0.390 T. Calculate the magnitude of the magnetic force on the wire assuming the angle between the magnetic field and the current is (a) 60.0, (b) 90.0, and (c) 120.arrow_forwardRank the magnitudes of the following magnetic fields from largest to smallest, noting any cases of equality. (a) the field 2 cm away from a long, straight wire carrying a current of 3 A (b) the Held at the center of a flat, compact, circular coil, 2 cm in radius, with 10 turns, carrying a current of 0.3 A (c) the field at the center of a solenoid 2 cm in radius and 200 cm long, with 1 000 turns, carrying a current of 0.3 A (d) the field at the center of a long, straight, metal bar, 2 cm in radius, carrying a current of 300 (e) a field of 1 mTarrow_forwardA magnetic field directed into the page changes with time according to B = 0.030 0t2 + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see Fig. P23.28). When t = 3.00 s and r2 = 0.020 0 m, what are (a) the magnitude and (b) the direction of the electric field at point P2?arrow_forward
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Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY