BIOCHEMISTRY
9th Edition
ISBN: 2818440090622
Author: BERG
Publisher: MAC HIGHER
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Chapter 31, Problem 33P
Interpretation Introduction
Interpretation:
The mechanism by which the ribosome identifies the AUG start codon, should be determined.
Concept introduction:
Protein synthesis (translation) is a process of generating new protein sequences inside the cell. This process takes place in the cytoplasm of the cell. This process is balanced by the degradation or export of cellular proteins. It is constituted of three steps namely, initiation, elongation, and termination.
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Students have asked these similar questions
Open reading frames...
correspond to introns, which are not read by the ribosome during translation
correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in a particular frame
correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in any of six frames
are often rich in acetylated histones which allow transcription
occur when fragments of DNA sequence are highly similar between two species
are recognized by ribosomes to initiate translation
Translation. Write the anti-codon sequence of the MRNA transcript. Translate the
MRNA transcript into peptide sequence using both the 3 letter abbreviation and 1 letter
abbreviation.
ANTI-CODON
3'
5'
SEQUENCE
AMINO ACID
N-
C-
SEQUENCE (3 letter terminus
Abbreviation)
Terminus
AMINO ACID
N-
C-
SEQUENCE (1 letter terminus
Abbreviation)
Terminus
Multiple choice A. The role of tRNA in translation is to
be translated by a ribosome.
incorporate into a polypeptide chain.
attach amino acids to a polypeptide chain.
carry amino acids to the ribosome.
Multiple choice B.
Translation continues until
the ribosome falls off the end of the RNA.
the ribosome encounters a transcriptional termination site.
the ribosome encounters a stop codon.
the ribosome falls off the DNA.
Chapter 31 Solutions
BIOCHEMISTRY
Ch. 31 - Prob. 1PCh. 31 - Prob. 2PCh. 31 - Prob. 3PCh. 31 - Prob. 4PCh. 31 - Prob. 5PCh. 31 - Prob. 6PCh. 31 - Prob. 7PCh. 31 - Prob. 8PCh. 31 - Prob. 9PCh. 31 - Prob. 10P
Ch. 31 - Prob. 11PCh. 31 - Prob. 12PCh. 31 - Prob. 13PCh. 31 - Prob. 14PCh. 31 - Prob. 15PCh. 31 - Prob. 16PCh. 31 - Prob. 17PCh. 31 - Prob. 18PCh. 31 - Prob. 19PCh. 31 - Prob. 20PCh. 31 - Prob. 21PCh. 31 - Prob. 22PCh. 31 - Prob. 23PCh. 31 - Prob. 24PCh. 31 - Prob. 25PCh. 31 - Prob. 26PCh. 31 - Prob. 27PCh. 31 - Prob. 28PCh. 31 - Prob. 29PCh. 31 - Prob. 30PCh. 31 - Prob. 31PCh. 31 - Prob. 32PCh. 31 - Prob. 33PCh. 31 - Prob. 34PCh. 31 - Prob. 35PCh. 31 - Prob. 36PCh. 31 - Prob. 37PCh. 31 - Prob. 38PCh. 31 - Prob. 39PCh. 31 - Prob. 40PCh. 31 - Prob. 41PCh. 31 - Prob. 42PCh. 31 - Prob. 43PCh. 31 - Prob. 44PCh. 31 - Prob. 45PCh. 31 - Prob. 46PCh. 31 - Prob. 47PCh. 31 - Prob. 48PCh. 31 - Prob. 49PCh. 31 - Prob. 50PCh. 31 - Prob. 51PCh. 31 - Prob. 52P
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- Given the following codons and their corresponding amino acids: UUU-Phenylalanine GAA- Glutamate CAA- Glutamine AAU- Asparagine AAC- Asn AAA- Lysine UCU- Serine GGA-Glycine ACC-Threonine AUG- Met/ START codon CCU- Proline GUU- Valine UAU-Tyrosine UAA- STOP AGG- Arginine AUU- Isoleucine CAU- Histidine GCU- Alanine UGU-Cysteir GAU-Asparti CUA-Leucine UGG-Tryptol CGU-Arginin Box 1: Show the mRNA sequence which codes for the short peptide, lys-ala-phe- leu. Include what should come before and after this short message. Don't leave any spaces between the letters. Box 2: Show the tRNA anticodon sequence that would line up with the mRNA strand from Box 1. Don't leave any spaces between the letters. Box 3 & 4: Show the DNA base sequence that would be found in the DNA double helix which carries the gene for this peptide. Give the coding strand sequence in Box 3 and template strand sequence in Box 4. Don't leave any spaces between the letters. Box 5: What if there was a frameshift at leucine…arrow_forwardTRANSCRIPTION The DNA provided for your animal is one side of the double helix. DNA - MRNA otein 1. Transcribe the DNA strand into mRNA. Don't forget the special base pair → rules for RNA! AU TA VERSION 1 2. Translate the mRNA into an amino acid chain. Notice that this is broken into 1 nucleotide sequences called CODONS. Use the codon chart to find the correct amino acids. Remember, translation for each chain always starts with the amino acid methionine (Met) and ends with one of the stop codons (UGA, UAG, UAA). C G Cheatham G C oints Fuer DNA TAC ATA A CA GTC стт TAG CT A AT C TAC T GG ACA GGT ACC ATA ACT = activity you mber to deter = may code Fuer MRNA veral thousar ctivity takes on 2). And se AA o pp DNA TA C C G T CcC A GT GT C T G C A A A ACT TAC GACAGC TAC GT G G C T сс ATC Turn in lete all tables MRNA AA n Synthesis mment DNA TAC сТА CT T G T C T T G G C C ACG AT T TAC CAT C C G GA C GG G TAC T TA A T C Class comme to Sea aclass comm MRNA AAarrow_forwardAAAGAGAAAAGAAUA to AAAGAGAAAUGAAUA. Suppose the codon sequence has a single base pair mutation If the old protein sequence was Lys-Glu-Lys-Arg-Ile, what will be the new sequence encoded by the mutant gene? (Use the 3-letter amino acid abbreviations with hyphens and no spaces in between, i.e. Ser-Asn-Tyr-Leu-Pro.) Submit Answer Retry Entire Group No more group attempts remainarrow_forward
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