Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 3.15, Problem 82SEP
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Explain why the iron and tungsten being BCC have different atomic radius but same atomic packing factor.
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Chapter 3 Solutions
Foundations of Materials Science and Engineering
Ch. 3.15 - Prob. 1KCPCh. 3.15 - Prob. 2KCPCh. 3.15 - Prob. 3KCPCh. 3.15 - Prob. 4KCPCh. 3.15 - Prob. 5KCPCh. 3.15 - Prob. 6KCPCh. 3.15 - Prob. 7KCPCh. 3.15 - Prob. 8KCPCh. 3.15 - Prob. 9KCPCh. 3.15 - Prob. 10KCP
Ch. 3.15 - Prob. 11KCPCh. 3.15 - Prob. 12KCPCh. 3.15 - Prob. 13KCPCh. 3.15 - Prob. 14KCPCh. 3.15 - Prob. 15KCPCh. 3.15 - Prob. 16KCPCh. 3.15 - Prob. 17KCPCh. 3.15 - Prob. 18KCPCh. 3.15 - Prob. 19KCPCh. 3.15 - Prob. 20KCPCh. 3.15 - Prob. 21KCPCh. 3.15 - Prob. 22KCPCh. 3.15 - Prob. 23KCPCh. 3.15 - Prob. 24AAPCh. 3.15 - Prob. 25AAPCh. 3.15 - Prob. 26AAPCh. 3.15 - Prob. 27AAPCh. 3.15 - Prob. 28AAPCh. 3.15 - Prob. 29AAPCh. 3.15 - Prob. 30AAPCh. 3.15 - Prob. 31AAPCh. 3.15 - Prob. 33AAPCh. 3.15 - A direction vector passes through a unit cube from...Ch. 3.15 - Prob. 36AAPCh. 3.15 - Prob. 37AAPCh. 3.15 - Prob. 38AAPCh. 3.15 - Prob. 41AAPCh. 3.15 - Prob. 42AAPCh. 3.15 - Prob. 43AAPCh. 3.15 - Prob. 44AAPCh. 3.15 - Prob. 45AAPCh. 3.15 - Prob. 46AAPCh. 3.15 - Prob. 47AAPCh. 3.15 - Rodium is FCC and has a lattice constant a of...Ch. 3.15 - Prob. 49AAPCh. 3.15 - Prob. 50AAPCh. 3.15 - Prob. 51AAPCh. 3.15 - Prob. 52AAPCh. 3.15 - Prob. 53AAPCh. 3.15 - Prob. 54AAPCh. 3.15 - Prob. 55AAPCh. 3.15 - Determine the Miller-Bravais direction indices of...Ch. 3.15 - Determine the Miller-Bravais direction indices of...Ch. 3.15 - Prob. 58AAPCh. 3.15 - Prob. 59AAPCh. 3.15 - Prob. 60AAPCh. 3.15 - Prob. 61AAPCh. 3.15 - Prob. 62AAPCh. 3.15 - Prob. 63AAPCh. 3.15 - Prob. 64AAPCh. 3.15 - Prob. 65AAPCh. 3.15 - Prob. 66AAPCh. 3.15 - Prob. 67AAPCh. 3.15 - Prob. 68AAPCh. 3.15 - Prob. 69AAPCh. 3.15 - Prob. 70AAPCh. 3.15 - Prob. 71AAPCh. 3.15 - Prob. 72AAPCh. 3.15 - Prob. 73AAPCh. 3.15 - Prob. 74SEPCh. 3.15 - Prob. 75SEPCh. 3.15 - Prob. 76SEPCh. 3.15 - Assuming that the volume of an HCP metal cell...Ch. 3.15 - Prob. 79SEPCh. 3.15 - Prob. 80SEPCh. 3.15 - Prob. 81SEPCh. 3.15 - Prob. 82SEPCh. 3.15 - Prob. 83SEPCh. 3.15 - Prob. 84SEPCh. 3.15 - Prob. 85SEPCh. 3.15 - Prob. 86SEPCh. 3.15 - Prob. 87SEPCh. 3.15 - Prob. 88SEPCh. 3.15 - Prob. 89SEPCh. 3.15 - Prob. 90SEPCh. 3.15 - Prob. 91SEPCh. 3.15 - Prob. 92SEPCh. 3.15 - Prob. 93SEPCh. 3.15 - Prob. 94SEPCh. 3.15 - Prob. 95SEPCh. 3.15 - Prob. 96SEP
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- 1. Show that the atomic packing factor for HCP is 0.74.2. Calculate the radius of Palladium atom given that PD has an FCC crystal structure, a density of 12.0 g/cm3, and an atomic weight of 106.4 g/mol.arrow_forwardA hypothetical metal has the SC crystal structure, a density of 7.08 g/cm3, and an atomic weight of 51.63 g/mol. The atomic radius of this metal in nanometer isarrow_forwardThe density of a sample of HCP beryllium is 1.844 g/cm 3 , and the lattice parameters are a 0 = 0.22858 nm and c 0 = 0.35842 nm. Calculate (a) the fraction of the lattice points that contains vacancies: and (b) the total number of vacancies in a cubic centimetre of Bearrow_forward
- Molybdenum has an atomic radius of 0.145nm. The volume of its cubic unit cell is0.0375 nm3 . What is the geometry of the molybdenum unit cell?arrow_forwardA paper clip has a mass of 10.75 grams and is made of gold. (FCC, R = 0.1442 nm), calculate: a) The number of unit cells in the sample volume. b) The number of atoms contained in the volume of the sample.arrow_forwardProf that the relation between atomic radius and lattice constant for FCC is a- 4r/V3 ? Question #3/ The atomic weight 207.2 (g/mol), crystal structure FCC, and atomic radius 0.175 nm, compute the theoretical densities of leadarrow_forward
- With a hexagonal crystal structure where a0=0.22858nm, co=0.35842nm, an atomic radius of 0.1143nm, density of 1.848g/cm3, and an atomic weight of 9.01g/mol, what is a)number of atoms in each unit cell and b) the packing factor in each unit cell.arrow_forwardCalculate the number of vacancies per cubic meter for some metal, M, at 811°C. The energy for vacancy formation is 0.89 eV/atom, while the density and atomic weight for this metal are 6.96 g/cm3 (at 811°C) and 55.72 g/mol, respectively.arrow_forwardThe crystalline density of polypropyleneis 0.946 g>cm3, and its amorphous densityis 0.855 g>cm3. What is the weight percentof the structure that is crystalline ina polypropylene that has a density of0.9 g>cm3?arrow_forward
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