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Concept explainers
(a)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
Root word represents the longest continuous carbon skeleton of the organic molecule.
(b)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton of the organic molecule.
(c)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton of the organic molecule.
(d)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton of the organic molecule.
(e)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton of the organic molecule.
(f)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton of the organic molecule.
(g)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton of the organic molecule.
(h)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton of the organic molecule.
(i)
Interpretation:
The IUPAC systematic name should be given for the given organic compound.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
Root word represents the longest continuous carbon skeleton of the organic molecule.
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Chapter 3 Solutions
Organic Chemistry; Modified MasteringChemistry with Pearson eText -- ValuePack Access Card; Study Guide and Student Solutions Manual for Organic Chemistry, Books a la Carte Edition (7th Edition)
- a. The following compounds have the same molecular formula as benzene. How many monobrominated products could each form? 1. HC‚CC‚CCH2CH3 2. CH2“CHC‚CCH“CH2 b. How many dibrominated products could each of the preceding compounds form? (Do not include stereoisomers.) c. How many dibrominated products could each of the compounds form if stereoisomers are included?arrow_forwardCH2 H3C H3C COOH Reagents e. PB13 f. NaCN then H3O* g. NBS, CCI4 h. CrO3, H2SO4 а. HBr b. Mg, ether c. CO2, ether then H3O* d. BH3, THF then H2O2, OH"arrow_forwardDraw the products formed when CH3CH2C ≡ C−Na+reacts with each compound. a. CH3CH2CH2Brb. (CH3)2CHCH2CH2Clc. (CH3CH2)3CCld. BrCH2CH2CH2CH2OHe. ethylene oxide followed by H2Of. propene oxide followed by H2Oarrow_forward
- Name each alkene: a. CH3CH=CHCH2CH2CH3 b. CH3CH=CH2 c. CH2CH3 l CH2=CHCH2CHCH3arrow_forward1. Name each of the following: CH3 CH3 CH3CCH₂CHCH₂CH3 a. d. CH3 CH3 Br "Z" b. CH₂CH3 CH3CH=CHCHCH3 e. CH3CH₂CCH2CH3 0 C. CH3 C₂H5arrow_forwardWhich structure is a meso compound? A. В. С. D. CH3 CH 3 CH3 CH 3 H--C1 H--C1 H--C1 H--C1 cl-- - CH3 Cl--H H--C1 Cl--H CH 3 CH2CH3 CH2CH3arrow_forward
- Provide the IUPAC names for the following compounds. Compound IUPAC Name 1. H3Ç CH3 H2C=CHCHCCH3 CHa 2. CH3 CH3CH2CH=CH2CH3 3. CH3 CH3CH=CHCHCH=CHCHCH3 CH3 4. CH3CHCH2CH3 CH3CH2CH2CH=CHCHCH2CH3 5. „CH3 CH3arrow_forwardReagents available f. PBr3 g. Mg, ether a. CH3CH,COCH b. C6H5 COCI c. AlCl3 d. NaBH₁, ethanol e. H₂SO4, dil am h. H₂SO4, conc i. SOCI₂ j. C6H5 CNarrow_forward1. Using Br2 in C2H4Br2 will result in HBr and ______. a. C2H3Cl3 b. C2H4Cl3 c. C2H2Cl3 d. none of the above 2. How many halogenation are posible in propane? a. 3 b. 8 c. 6 d. 10 3.Sulfonation of pentane will result in ________ and water. a. C5H11SO3H b. C5H12SO3H c. C5H14SO3H d. none of the above 4.Nitration of hexane will result in ________ and water. a. C6H13SO3H b. C6H15NO2 c. C6H13NO2 d. C6H14NO2 5.How many moles of O2 in heating a C12H26 (dodecane) a. 27 b. 37 c. 24 d. none of the abovearrow_forward
- Give the IUPAC name for each compound. OH a. CH3CH(CH₂)4CH3 (select) OH (CH3CH₂)2CHCHCH₂CH3 (select) b. C. d. CH3 OH (select) (select) (select) OH (select) (select) (select)arrow_forward1. Provide proper IUPAC names for the following compounds. a. CH3 | CH3C CCHCH2CH2CH3 CH3 Br b. H₂C=CH-C-CH-CC-H | CH3 C.arrow_forwardName each alkyne. a. CH=C-CH-CH3 CH3 b. CH3-C=C-CH-CH-CH,-CH, CH3 CH3 c. CHEC-C-CH,-CH3 CH2 ČH, CH3 d. CH;-C=C-CH-C-CH, CH2 CH3 ČH3arrow_forward
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