BIOCHEMISTRY
9th Edition
ISBN: 2818440090622
Author: BERG
Publisher: MAC HIGHER
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Chapter 32, Problem 3P
Interpretation Introduction
Interpretation:
The expected number of times an 8 bp, 10 bp, and 12bp DNA site would be present in E. Coli, should be calculated.
Concept introduction:
The building block of DNA and RNA is termed as the
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Backward? Bacteriophage T7 helicase moves along DNA in the 5'-to-
3'5'-to-3' direction. Other helicases have been reported to move in
the 3'-to-5'3'-to-5' direction. Is there any fundamental reason why
you would expect helicases to move in one direction or the other?
Read it carefully.. Draw only correct diagrams..
In the Watson-Crick DNA base pairing model, Adenine (A) binds to thymine (T), guanine (G) binds to cytosine (C).
1. Draw the structures of thymine and adenine stabilized by Watson-Crick base pair interaction.
2. Also draw the structure of the amide group of glutamine in an interaction of this T-A pair in a way that maximally satisfies the hydrogen bonding capacity of amide.
gene. If the JM109 strain is transformed by the PBKSK plasmid, the strain will produce the B-galactosidase (from the lac gene)
and will hydrolyze X-gal to produce the blue compound. Therefore, colonies that were transformed and contain the pBSKS wil
you
appear blue.
IPTG &
X-Gal &
NO colonies
Amp
E. coli JM109
E. coli JM109
50 mM calcium
chloride-15% glycerol
lac
lac
lac
IPTG &
I Recovery
X-Gal
solution at -702C
PBSKS
White colonies
E. coli JM109
E. coli JM109
ampR
amp I
amp
lac
lac
Heat Shock
Non-transformed
42°C
E. coli JM109
E. coli JM109
amps
amps
lac
lac
IPTG &
X-Gal
lac I
Recovery
lac
PBSKS
BLUE colonies
PBSKS
ampRI
(amp
Transformed
IPTG &
X-Gal &
BLUE colonies
Amp
Hypotheses: Circle the correct answer
1. If PBSKS is transformed into JM109 cells, colonies will be (able/not able) to grow in the presence of ampicillin.
a. Why?
_
2. If PBSKS is transformed into JM109 cells, colonies in media with IPTG (will/will not) induce the production the B-
galactosidase enzyme.
a. Why?_
3. If…
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