PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
8th Edition
ISBN: 9781337904285
Author: Larson
Publisher: CENGAGE L
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Chapter 3.4, Problem 107E

a.

To determine

To find:

An interval containing the solution of the equation by completing the table.

a.

Expert Solution
Check Mark

Answer to Problem 107E

Our required interval would be (0.8,0.9) .

Explanation of Solution

Given:

A logarithmic equation and a table: e3x=12 .

    x 0.60.70.80.91.0

      e3x

Calculation:

To complete the table, we will substitute the values of x in our given expression as shown below:

  e3xe3(0.6)e1.86.049647466.050

  e3xe3(0.7)e2.18.166169918.166

  e3xe3(0.8)e2.411.0231763811.023

  e3xe3(0.9)e2.714.8797317214.880

  e3xe3(1.0)e3.020.085536920.086

The complete table would be:

    x 0.6 0.7 0.8 0.9 1.0

      e3x

    6.0508.16611.02314.880 20.086

Since 12 lies between 11.023and 14.880, therefore our required interval would be (0.8,0.9) .

b.

To determine

To graph:

The given function using a graphing utility and approximate the solution.

b.

Expert Solution
Check Mark

Answer to Problem 107E

The solution of our given equation would be x=0.828 .

Explanation of Solution

Given:

A logarithmic equation: e3x=12 .

Calculation:

Upon graphing our given function, we will get our required graph as shown below:

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 3.4, Problem 107E

We can see that both lines intersect at x=0.828 , therefore, x=0.828 is a solution for our given function.

c.

To determine

To solve:

The given equation algebraically.

c.

Expert Solution
Check Mark

Answer to Problem 107E

The solution of our given equation would be x0.828 .

Explanation of Solution

Given:

A logarithmic equation: e3x=12 .

Calculation:

We will use logarithmic properties to solve our given equation.

  e3x=12 (Given equation)ln(e3x)=ln(12) (Taking natural log on both sides)3xln(e)=ln(12) (Using property ln(xm)=mln(x))3x=ln(12) (Using property ln(e)=1)3x3=2.4849066493 (Dividing both sides by 3)x=0.828302216x0.828 (Rounding to three decimal places)

Therefore, the solution of our given equation would be x0.828 .

Chapter 3 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

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Prob. 42CRCh. 3 - Prob. 43CRCh. 3 - Prob. 44CRCh. 3 - Prob. 45CRCh. 3 - Prob. 46CRCh. 3 - Prob. 47CRCh. 3 - Prob. 48CRCh. 3 - Prob. 49CRCh. 3 - Prob. 50CRCh. 3 - Prob. 51CRCh. 3 - Prob. 52CRCh. 3 - Prob. 53CRCh. 3 - Prob. 54CRCh. 3 - Prob. 55CRCh. 3 - Prob. 56CRCh. 3 - Prob. 57CRCh. 3 - Prob. 58CRCh. 3 - Prob. 59CRCh. 3 - Prob. 60CRCh. 3 - Prob. 61CRCh. 3 - Prob. 62CRCh. 3 - Prob. 63CRCh. 3 - Prob. 64CRCh. 3 - Prob. 65CRCh. 3 - Prob. 66CRCh. 3 - Prob. 67CRCh. 3 - Prob. 68CRCh. 3 - Prob. 69CRCh. 3 - Prob. 70CRCh. 3 - Prob. 71CRCh. 3 - Prob. 72CRCh. 3 - Prob. 73CRCh. 3 - Prob. 74CRCh. 3 - Prob. 75CRCh. 3 - Prob. 76CRCh. 3 - Prob. 77CRCh. 3 - Prob. 78CRCh. 3 - Prob. 79CRCh. 3 - Prob. 80CRCh. 3 - Prob. 81CRCh. 3 - Prob. 82CRCh. 3 - Prob. 83CRCh. 3 - Prob. 84CRCh. 3 - Prob. 85CRCh. 3 - Prob. 86CRCh. 3 - Prob. 87CRCh. 3 - Prob. 88CRCh. 3 - Prob. 89CRCh. 3 - Prob. 90CRCh. 3 - Prob. 91CRCh. 3 - Prob. 92CRCh. 3 - Prob. 93CRCh. 3 - Prob. 94CRCh. 3 - Prob. 95CRCh. 3 - Prob. 96CRCh. 3 - Prob. 97CRCh. 3 - 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Prob. 27CTCh. 3 - Prob. 28CTCh. 3 - Prob. 29CTCh. 3 - Prob. 30CTCh. 3 - Prob. 1STPCh. 3 - Prob. 2STPCh. 3 - Prob. 3STPCh. 3 - Prob. 4STPCh. 3 - Prob. 5STPCh. 3 - Prob. 6STPCh. 3 - Prob. 7STPCh. 3 - Prob. 8STPCh. 3 - Prob. 9STPCh. 3 - Prob. 10STPCh. 3 - Prob. 11STPCh. 3 - Prob. 12STPCh. 3 - Prob. 13STPCh. 3 - Prob. 14STPCh. 3 - Prob. 15STPCh. 3 - Prob. 16STPCh. 3 - Prob. 17STPCh. 3 - Prob. 18STPCh. 3 - Prob. 19STPCh. 3 - Prob. 20STPCh. 3 - Prob. 21STPCh. 3 - Prob. 22STPCh. 3 - Prob. 23STPCh. 3 - Prob. 24STPCh. 3 - Prob. 25STPCh. 3 - Prob. 26STP
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