PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
8th Edition
ISBN: 9781337904285
Author: Larson
Publisher: CENGAGE L
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Question
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Chapter 3.4, Problem 93E
To determine

To solve the equation and identify the extraneous solution.

Expert Solution & Answer
Check Mark

Answer to Problem 93E

The solution of the equation is x=3 andthe extraneous solution is x=−2

Explanation of Solution

Given information: The given equation is ln(x+5)=ln(x−1)+ln(x+1)

Calculation:

Algebraic solution

  ln(x+5)=ln(x−1)+ln(x+1)     [write original equation]ln(x+5)=ln[(x−1)(x+1) ]      [use properties of logarithms]x+5=[(x+1)(x−1)]                 [one to one property]x+5=x2−1x2−x−6=0                              [add −(x+5) to both side](x−3)(x+2)=0                        [factors]x=−2                         set 1st factor equal to 0x=3                           set 2nd factor equal to 0

Check possible solution in the original equation

  ln(3+5)=ln(3−1)+ln(3+1)  [substitute x=3] 2.079=2.079                             [use calculator]

The solution of the equation is x=3

It can be concluded that x=−2 is not valid because −2 is not in the range of natural logarithmic function.

Therefore,

The extraneous solution is x=−2

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Chapter 3.4, Problem 92E
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Chapter 3.4, Problem 94E

Chapter 3 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

Ch. 3.1 - Prob. 1ECh. 3.1 - Prob. 2ECh. 3.1 - Prob. 3ECh. 3.1 - Prob. 4ECh. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10E
Ch. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.1 - Prob. 35ECh. 3.1 - Prob. 36ECh. 3.1 - Prob. 37ECh. 3.1 - Prob. 38ECh. 3.1 - Prob. 39ECh. 3.1 - Prob. 40ECh. 3.1 - Prob. 41ECh. 3.1 - Prob. 42ECh. 3.1 - Prob. 43ECh. 3.1 - Prob. 44ECh. 3.1 - Prob. 45ECh. 3.1 - Prob. 46ECh. 3.1 - Prob. 47ECh. 3.1 - Prob. 48ECh. 3.1 - Prob. 49ECh. 3.1 - Prob. 50ECh. 3.1 - Prob. 51ECh. 3.1 - Prob. 52ECh. 3.1 - Prob. 53ECh. 3.1 - Prob. 54ECh. 3.1 - Prob. 55ECh. 3.1 - Prob. 56ECh. 3.1 - Prob. 57ECh. 3.1 - Prob. 58ECh. 3.1 - Prob. 59ECh. 3.1 - Prob. 60ECh. 3.1 - Prob. 61ECh. 3.1 - Prob. 62ECh. 3.1 - Prob. 63ECh. 3.1 - 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Prob. 98ECh. 3.4 - Prob. 99ECh. 3.4 - Prob. 100ECh. 3.4 - Prob. 101ECh. 3.4 - Prob. 102ECh. 3.4 - Prob. 103ECh. 3.4 - Prob. 104ECh. 3.4 - Prob. 105ECh. 3.4 - Prob. 106ECh. 3.4 - Prob. 107ECh. 3.4 - Prob. 108ECh. 3.4 - Prob. 109ECh. 3.4 - Prob. 110ECh. 3.4 - Prob. 111ECh. 3.4 - Prob. 112ECh. 3.4 - Prob. 113ECh. 3.4 - Prob. 114ECh. 3.4 - Prob. 115ECh. 3.4 - Prob. 116ECh. 3.4 - Prob. 117ECh. 3.4 - Prob. 118ECh. 3.4 - Prob. 119ECh. 3.4 - Prob. 120ECh. 3.4 - Prob. 121ECh. 3.4 - Prob. 122ECh. 3.4 - Prob. 123ECh. 3.4 - Prob. 124ECh. 3.4 - Prob. 125ECh. 3.4 - Prob. 126ECh. 3.4 - Prob. 127ECh. 3.4 - Prob. 128ECh. 3.4 - Prob. 129ECh. 3.4 - Prob. 130ECh. 3.4 - Prob. 131ECh. 3.4 - Prob. 132ECh. 3.4 - Prob. 133ECh. 3.4 - Prob. 134ECh. 3.4 - Prob. 135ECh. 3.4 - Prob. 136ECh. 3.4 - Prob. 137ECh. 3.4 - Prob. 138ECh. 3.4 - Prob. 139ECh. 3.4 - Prob. 140ECh. 3.4 - Prob. 141ECh. 3.4 - Prob. 142ECh. 3.4 - Prob. 143ECh. 3.4 - Prob. 144ECh. 3.4 - Prob. 145ECh. 3.4 - Prob. 146ECh. 3.5 - Prob. 1ECh. 3.5 - Prob. 2ECh. 3.5 - Prob. 3ECh. 3.5 - Prob. 4ECh. 3.5 - Prob. 5ECh. 3.5 - Prob. 6ECh. 3.5 - Prob. 7ECh. 3.5 - Prob. 8ECh. 3.5 - Prob. 9ECh. 3.5 - Prob. 10ECh. 3.5 - Prob. 11ECh. 3.5 - Prob. 12ECh. 3.5 - Prob. 13ECh. 3.5 - Prob. 14ECh. 3.5 - Prob. 15ECh. 3.5 - Prob. 16ECh. 3.5 - Prob. 17ECh. 3.5 - Prob. 18ECh. 3.5 - Prob. 19ECh. 3.5 - Prob. 20ECh. 3.5 - Prob. 21ECh. 3.5 - Prob. 22ECh. 3.5 - Prob. 23ECh. 3.5 - Prob. 24ECh. 3.5 - Prob. 25ECh. 3.5 - Prob. 26ECh. 3.5 - Prob. 27ECh. 3.5 - Prob. 28ECh. 3.5 - Prob. 29ECh. 3.5 - Prob. 30ECh. 3.5 - Prob. 31ECh. 3.5 - Prob. 32ECh. 3.5 - Prob. 33ECh. 3.5 - Prob. 34ECh. 3.5 - Prob. 35ECh. 3.5 - Prob. 36ECh. 3.5 - Prob. 37ECh. 3.5 - Prob. 38ECh. 3.5 - Prob. 39ECh. 3.5 - Prob. 40ECh. 3.5 - Prob. 41ECh. 3.5 - Prob. 42ECh. 3.5 - Prob. 43ECh. 3.5 - Prob. 44ECh. 3.5 - Prob. 45ECh. 3.5 - Prob. 46ECh. 3.5 - Prob. 47ECh. 3.5 - Prob. 48ECh. 3.5 - Prob. 49ECh. 3.5 - Prob. 50ECh. 3.5 - Prob. 51ECh. 3.5 - Prob. 52ECh. 3.5 - Prob. 53ECh. 3.5 - Prob. 54ECh. 3.5 - Prob. 55ECh. 3.5 - 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Implicit Differentiation with Transcendental Functions; Author: Mathispower4u;https://www.youtube.com/watch?v=16WoO59R88w;License: Standard YouTube License, CC-BY
How to determine the difference between an algebraic and transcendental expression; Author: Study Force;https://www.youtube.com/watch?v=xRht10w7ZOE;License: Standard YouTube License, CC-BY