PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
8th Edition
ISBN: 9781337904285
Author: Larson
Publisher: CENGAGE L
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Chapter 3.4, Problem 142E
To determine

Is the time required for a continuously compoundedinvestment to quadruple twice as long as the time required for it to double? Give a reason for your answer and verify your answer algebraically.

Expert Solution & Answer
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Answer to Problem 142E

The time required for a continuously compounded investment to quadruple is twice as long as the time required for it to double.

Explanation of Solution

Concept used:

Continuous compound interest formula- A=Pert , where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form.

Calculation:

Let us assume that the principal amount is P and annual interest rate is r.

The double of principal would be 2P.

Upon substituting our given values in continuous compound interest formula, we will get:

  A=Pert (Continuous compound interest formula)2P=Pert (Substituting A=2P)2PP=PertP (Dividing both sides by P)2=ertert=2 (Switching sides)ln(ert)=ln(2) (Taking natural log on both sides)rtln(e)=ln(2) (Using property ln(xm)=mln(x))rt=ln(2) (Using property ln(e)=1)t=ln(2)r

The quadruple of principal would be 4P.

  A=Pert (Continuous compound interest formula)4P=Pert (Substituting A=4P)4PP=PertP (Dividing both sides by P)4=ertert=22 (Switching sides)ln(ert)=ln(22) (Taking natural log on both sides)rtln(e)=2ln(2) (Using property ln(xm)=mln(x))rt=2ln(2) (Using property ln(e)=1)t=2ln(2)r

Upon comparing both times, we will get:

  Quadrupling timeDoubling time=2ln(2)rln(2)r=2ln(2)ln(2)=21

Therefore, the time required for a continuously compounded investment to quadruple is twice as long as the time required for it to double.

Chapter 3 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

Ch. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.1 - Prob. 35ECh. 3.1 - Prob. 36ECh. 3.1 - Prob. 37ECh. 3.1 - Prob. 38ECh. 3.1 - Prob. 39ECh. 3.1 - Prob. 40ECh. 3.1 - Prob. 41ECh. 3.1 - Prob. 42ECh. 3.1 - Prob. 43ECh. 3.1 - Prob. 44ECh. 3.1 - Prob. 45ECh. 3.1 - Prob. 46ECh. 3.1 - Prob. 47ECh. 3.1 - Prob. 48ECh. 3.1 - Prob. 49ECh. 3.1 - Prob. 50ECh. 3.1 - Prob. 51ECh. 3.1 - Prob. 52ECh. 3.1 - Prob. 53ECh. 3.1 - Prob. 54ECh. 3.1 - Prob. 55ECh. 3.1 - Prob. 56ECh. 3.1 - Prob. 57ECh. 3.1 - Prob. 58ECh. 3.1 - Prob. 59ECh. 3.1 - Prob. 60ECh. 3.1 - Prob. 61ECh. 3.1 - Prob. 62ECh. 3.1 - Prob. 63ECh. 3.1 - 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