8th Edition

ISBN: 9781337904285

Author: Larson

Publisher: CENGAGE L

Concept explainers

The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.

Speed, Time, and Distance

Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …

Profit and Loss

The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.

Units and Measurements

Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…

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Question

Chapter 3.2, Problem 128E

To determine

To calculate: the number of months it would take for the average score in Example 10 to decrease to 60 , using a graphing calculator.

Explain the method of solving the problem.

Describe another way to use the graphing utility to determine the answer.

Based on the shape of the graph, explain whether the rate at which a student forgets information increase or decrease with time.

Expert Solution & Answer

Answer to Problem 128E

By using a graphing utility table feature, it can be concluded that in approximately 11 months the average score decreases to 60

Another method to solve the problem is by graphing a line y=60 in the same viewing window and finding the point of intersection of the two graphs.

Based on the shape of the graph, the rate at which students forgets information decreases, which may be due to consecutive retests.

Explanation of Solution

Given information:

Consider the information given in Example 10 .

The human memory model to determine the average score of the students every month after the exam:

f(t)=75−6ln(t+1)

Where t is the time in months.

As per the problem.

The function:

f(t)=75−6ln(t+1)

Use graphing utility to graph the function.

Step 1: Press WINDOW button to access the Window editor.

Step 2: Press Y= button.

Step 3: Enter the expression, f(t)=75−6ln(t+1) , which is required to graph.

Step 4: Press GRAPH button to graph the functions.

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 3.2, Problem 128E , additional homework tip 1

The table of values from the graph:

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 3.2, Problem 128E , additional homework tip 2

From the graph, it can be concluded that in approximately 11 months the average score decreases to 60

Another method to solve the problem is by graphing a line y=60 in the same viewing window as the function and finding the point of intersection of the two graphs.

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 3.2, Problem 128E , additional homework tip 3

The graph shows the two lines intersect at (11.182,60) .

The function f(t)=75−6ln(t+1) has a decreasing graph.

Based on the shape of the graph, the rate at which students forgets information decreases, which may be due to consecutive retests.

Chapter 3.2, Problem 127E

Chapter 3.2, Problem 129E

Chapter 3 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

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Prob. 111CR Ch. 3 - Prob. 112CR Ch. 3 - Prob. 113CR Ch. 3 - Prob. 114CR Ch. 3 - Prob. 115CR Ch. 3 - Prob. 116CR Ch. 3 - Prob. 117CR Ch. 3 - Prob. 118CR Ch. 3 - Prob. 119CR Ch. 3 - Prob. 120CR Ch. 3 - Prob. 121CR Ch. 3 - Prob. 122CR Ch. 3 - Prob. 123CR Ch. 3 - Prob. 124CR Ch. 3 - Prob. 125CR Ch. 3 - Prob. 126CR Ch. 3 - Prob. 1CT Ch. 3 - Prob. 2CT Ch. 3 - Prob. 3CT Ch. 3 - Prob. 4CT Ch. 3 - Prob. 5CT Ch. 3 - Prob. 6CT Ch. 3 - Prob. 7CT Ch. 3 - Prob. 8CT Ch. 3 - Prob. 9CT Ch. 3 - Prob. 10CT Ch. 3 - Prob. 11CT Ch. 3 - Prob. 12CT Ch. 3 - Prob. 13CT Ch. 3 - Prob. 14CT Ch. 3 - Prob. 15CT Ch. 3 - Prob. 16CT Ch. 3 - Prob. 17CT Ch. 3 - Prob. 18CT Ch. 3 - Prob. 19CT Ch. 3 - Prob. 20CT Ch. 3 - Prob. 21CT Ch. 3 - Prob. 22CT Ch. 3 - Prob. 23CT Ch. 3 - Prob. 24CT Ch. 3 - Prob. 25CT Ch. 3 - Prob. 26CT Ch. 3 - Prob. 27CT Ch. 3 - Prob. 28CT Ch. 3 - Prob. 29CT Ch. 3 - Prob. 30CT Ch. 3 - Prob. 1STP Ch. 3 - Prob. 2STP Ch. 3 - Prob. 3STP Ch. 3 - Prob. 4STP Ch. 3 - Prob. 5STP Ch. 3 - Prob. 6STP Ch. 3 - Prob. 7STP Ch. 3 - Prob. 8STP Ch. 3 - Prob. 9STP Ch. 3 - Prob. 10STP Ch. 3 - Prob. 11STP Ch. 3 - Prob. 12STP Ch. 3 - Prob. 13STP Ch. 3 - Prob. 14STP Ch. 3 - Prob. 15STP Ch. 3 - Prob. 16STP Ch. 3 - Prob. 17STP Ch. 3 - Prob. 18STP Ch. 3 - Prob. 19STP Ch. 3 - Prob. 20STP Ch. 3 - Prob. 21STP Ch. 3 - Prob. 22STP Ch. 3 - Prob. 23STP Ch. 3 - Prob. 24STP Ch. 3 - Prob. 25STP Ch. 3 - Prob. 26STP

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