Introduction to Electrodynamics
4th Edition
ISBN: 9781108420419
Author: David J. Griffiths
Publisher: Cambridge University Press
Textbook Question
Chapter 3.4, Problem 3.42P

You can use the superposition principle to combine solutionsobtained by separation of variables. For example, in Prob. 3.16 you found thepotential inside a cubical box, if five faces are grounded and the sixth is at a constant potential V 0 ; by a six-fold superposition of the result, you could obtain thepotential inside a cube with the faces maintained at specified constant voltages V 1 , V 2 , ... V 6 . In this way,using Ex. 3.4 and Prob. 3.15, find the potential inside arectangular pipe with two facing sides ( x = ± b ) at potential V 0 , a third ( y = a ) at V 1 , and the last (at y = 0 ) grounded.

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6sine 6cose Problem #5: Given the electric fiekd intensity vector E = R R? (V/m), R? A) Find the ekctric potential of point C with respect to point D if C (2 m, a/2, 1/2) and D (4 m, a/2, T/2). Sketch points Cand D, and the integration path taken. B) Find the electric potential of point B with respect to point D if B (2 m, a2, 0) and D (4 m, /2, T2). Sketch points B and D and the integration path taken. C) Find the electric potential of point A with respect to point D if A (2 m, 45°, 90°) and D (4 m, 90 *,90°). Sketch points A and D and the integration path taken. (Points A, B, C and D are in spherical coordinates).
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