Concept explainers
a.
To write: and graph
a.
Answer to Problem 12CFU
Explanation of Solution
Given information:
The number of weeks is represented by x and profit is represented by P.
Average yield per acre = 120 bushels
Selling price of one bushel = $0.48
Increase in yield after waiting for a week = 10 bushels
Decrease in selling price of one bushel after waiting for a week to harvest = $0.03
Calculation:
The selling price of 120 bushels =
The yield increase per week =
The change in selling price after waiting for a week =
The profit of soybeans after waiting for x week =
Thus, the profit function can be represented as follows:
The graph for
b.
To find: the number of weeks of waiting in order to maximize profit.
b.
Answer to Problem 12CFU
2 weeks
Explanation of Solution
Given information:
Calculation:
The x represents the number of weeks and y represents the profit. The maximum point in the graph
The maximum profit is $58.8 per bushel. Thus, the profit will be maximized in 2 weeks.
c.
To find: the maximum profit.
c.
Answer to Problem 12CFU
$58.8 per bushel
Explanation of Solution
Given information:
Calculation:
The x represents the number of weeks and y represents the profit. The maximum point in the graph
Thus the maximum profit is $58.8 per bushel.
d.
the risks of waiting.
d.
Answer to Problem 12CFU
Low yield of crops
Profit will decrease
Explanation of Solution
Given information:
Calculation:
The x represents the number of weeks and y represents the profit. The maximum point in the graph
From the graph it is evident that the crop yield and maximum profit will be after 2 weeks. If the crops are not harvested for more than 2 weeks then it will be ruined.
Thus, as the time of waiting (in weeks) is increased more than 2 weeks then the crops yield will be low and there will be loss in the profit.
Chapter 3 Solutions
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
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