Concept explainers
(a)
Interpretation:
The name of ionic compound formed from the ions
Concept Introduction:
An ionic compound has two elements one is metal and another one is non-metal. The metal ion always has positive charge and the nonmetal ion always has negative ion in binary compounds. Example:
The following rule can be used for the naming of binary ionic compounds.
The full name of the metallic element is given first, followed by a separate word containing the stem of the metallic element name and the suffix –ide.
The positive charge on metal ions from IA, IIA and IIIA is equal to the group number, while the negative charge on non-metal ions from VA, VIA and VIIA is equal to the group number eight.
(b)
Interpretation:
The chemical formula of ionic compound formed from the ions
Concept Introduction:
An ionic compound has two elements one is metal and another one is non-metal. The metal ion always has positive charge and the nonmetal ion always has negative ion in binary compounds. Example:
The following rule can be used for the naming of binary ionic compounds.
The full name of the metallic element is given first, followed by a separate word containing the stem of the metallic element name and the suffix –ide.
The positive charge on metal ions from IA, IIA and IIIA is equal to the group number, while the negative charge on non-metal ions from VA, VIA and VIIA is equal to the group number eight.
(c)
Interpretation:
The number of ions present in the formula unit of ionic compound formed from the ions
Concept Introduction:
An ionic compound has two elements one is metal and another one is non-metal. The metal ion always has positive charge and the nonmetal ion always has negative ion in binary compounds. Example:
The following rule can be used for the naming of binary ionic compounds.
The full name of the metallic element is given first, followed by a separate word containing the stem of the metallic element name and the suffix –ide.
The positive charge on metal ions from IA, IIA and IIIA is equal to the group number, while the negative charge on non-metal ions from VA, VIA and VIIA is equal to the group number eight.
(d)
Interpretation:
The number of electrons transferred per formula unit of ionic compound formed from the ions
Concept Introduction:
An ionic compound has two elements one is metal and another one is non-metal. The metal ion always has positive charge and the nonmetal ion always has negative ion in binary compounds. Example:
The following rule can be used for the naming of binary ionic compounds.
The full name of the metallic element is given first, followed by a separate word containing the stem of the metallic element name and the suffix –ide.
The positive charge on metal ions from IA, IIA and IIIA is equal to the group number, while the negative charge on non-metal ions from VA, VIA and VIIA is equal to the group number eight.
Want to see the full answer?
Check out a sample textbook solutionChapter 4 Solutions
General, Organic, and Biological Chemistry
- Give the total number of valence electrons in each of the following molecules. msp;a.N2Oc.C3H8b.B2H6d.NC13arrow_forwardWhich type of chemical model shows the bond angle and bond length between atoms in the compound? How does this type of model represent a compound?arrow_forwardBased on Lewis dot symbols, phosphorus forms a -3 ion because Group of answer choices it gains three electrons (dots) when forming an ionic compound. it loses five electrons (dots) when forming an ionic compound. it can form five covalent bonds. it needs two more electrons to meet the octet rule.arrow_forward
- Now, we will investigate diatomic molecules, those that are made up of two of the same type of atom. Select 2 fluorine atoms. How many valence electrons are in each fluorine atom? Is a fluorine atom a metal or a non-metal? Did the combination of these atoms create a covalent or ionic bond? How are the valence electrons organized to form a bond between these atoms? How is this different from the ionic bonds formed in the previous part of the activity?arrow_forwardIn drawing the Lewis structure of a polyatomic ion with a charge of 2-, you must adjust the electron count by: a. Subtracting 1 electron from the total number of valence electrons. b. Adding 1 more electron to the total number of valence electrons. c. Subtracting 2 electrons from the total number of valence electrons. d. Adding 2 more electrons to the total number of valence electrons.arrow_forwardPlease answer the following 6 questions below 1. Consider the following electronegativity values: Cl = 3.2, Si = 1.9, Ba = 0.9, Al = 1.6 When calculating the types of bonds these atoms can make, all of the following conclusions are true EXCEPT: a. The bond between Ba and Cl is expected to be ionic b. The bond between Cl and Si is expected to be polar covalent c. The bond between Al and Si is expected to be nonpolar covalent d. The bond between Al and Cl is expected to be ionic 2. Draw the lewis structures for both resonance structures of the OCBr+ ion and select the statement that is true a. The molecule sometimes looks like one resonances structure, and at other times it looks like the other resonance structure b. In one resonance structure, the carbon is in the center, and in the other one, the oxygen is in the center c. The bond between carbon and oxygen would best be described as 2.5 bonds (halfway between a double and a triple bond) d. In one resonance structure the positive…arrow_forward
- Answer the following questions relating to the chemistry of the halogens. (a) The molecular formulas of diatomic bromine, chlorine, fluorine, and iodine are written below. Circle the formula of the molecule that has the longest bond length. Justify your choice in terms of atomic structure. Br2 Cl2 F2 I2 Br2Br2 and Cl2Cl2 can react to form the compound BrClBrCl. A chemistry teacher wants to prepare Br2Br2. The teacher has access to the following three reagents: NaBr(aq)NaBr(��), Cl2(g)Cl2(�), and I2(s)I2(�). Half-Reaction E°�° at 25°C(V)25°C(V) Br2+2e−→2Br−Br2+2�−→2Br− 1.071.07 Cl2+2e−→2Cl−Cl2+2�−→2Cl− 1.361.36 I2+2e−→2I−I2+2�−→2I− 0.530.53 (b) Using the data in the table above, write the balanced equation for the thermodynamically favorable reaction that will produce Br2Br2 when the teacher combines two of the reagents. Justify that the reaction is thermodynamically favorable by calculating the value of E°�° for the reaction. (c) The boiling point of Br2Br2 is…arrow_forwardComplete each the following statements for a molecule of NI3:a) There are ___________ electron groups around the central N atom. b) The electron-group geometry is _________________. c) The number of bonded atoms attached to the central N atom is _________________. d) The shape of the molecule is ______________________. e) Based on electronegativities the N-I bond is _____________________. f) Overall, the molecule is ______________.arrow_forwardClassify the compound NF3 as ionic or covalent. What is the name of this compound? fill in the blank 22. Classify the compound K2CO3 as ionic or covalent? What is the name of this compound? fill in the blank 4 3. Classify the compound nickel(II) chloride as ionic or covalent. What is the formula for this compound? 4. Classify the compound dinitrogen tetroxide as ionic or covalent. What is the formula for this compound?arrow_forward
- PLEASE ANSWER THESE 3 MULTIPLE choices QUESTIONS Q1) What is the total number of electrons in the correct Lewis dot formula of the sulfite ion? a 8 b 24 c 26 d 30 e 32 Q2) In the Lewis structure for the OF2 molecule, the number of lone pairs of electrons around the central oxygen atoms is a 0 b 1 c 2 d 3 e 4 Q1) Francium has a higher electronegativity than fluorine. True Falsearrow_forwardThe bond that forms between two oxygen atoms to form O2, oxygen gas ... a) involves shared electrons b) is a polar covalent bond c) is a non-polar covalent bond d) a and b e) a and carrow_forwardFor each bond, show the direction of polarity by selecting the correct partial charges. Si-S Si-Cl Cl-S The most polar bond is _______.arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning