Fundamentals of Physics, Volume 1, Chapter 1-20
Fundamentals of Physics, Volume 1, Chapter 1-20
10th Edition
ISBN: 9781118233764
Author: David Halliday
Publisher: WILEY
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Chapter 40, Problem 17P
To determine

To calculate:

the magnitude of Bint

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F.j = (-e)(-v,k) × (B,i + B.k) ev Bzj. Solving for B gives F. Br 8.50x10 16 N = 1.13 T. Therefore B = 1.13 Ti – 0.772 Tk. The magnitude o A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.70 km/s in the +x-direction experiences a force of 2.10x10-16 N in the +y- direction, and an electron moving at 4.70 km/s in the eve (1.60x10 19 C)(4700 m/s) is B = VB? + B = (1.13 T)² + (-0.772 T)² = 1.37 T. -z-direction experiences a force of 8.50x10-16 N in the +y-direction. Part B For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a proton. What is the direction of the magnetic field? (in the xz-plane) Express your answer in degrees. 0 = 60.59 ° from the -z-direction to the +x-direction Submit Previous Answers Request Answer X Incorrect; Try Again; 9 attempts remaining
The potential energy of a magnetic moment in an external magnetic field is given by U = -u-B. The magnetic moment associated with the spin of an electron is 5.79 x 10-5 eV/T. Calculate the difference in energy between the two possible orientations of an electron in energy in a magnetic field B = (0.8 T) k. Answer in units of eV. %3D %3D If these electrons are bombarded with photons of energy equal to this energy difference, "spin flip" transitions can be induced. Find the wavelength of the photons needed for such transitions. (This phenomenon is called electron spin resonance.) Answer in units of cm.
An lithium nucleus has a velocity of v = (4.76 x 106 m/s) i – (2.75 x 106 m/s) j and travels through a region of space with a uniform magnetic field of B = (0.667 T) k This particle has a charge of +3e = +4.806 x 10 19 C and seven nucleons in the nucleus meaning it has a mass of 7u = 7(1.66 x 1027 kg) = 11.6 x 10-27 kg (a) Find the magnetic force on this particle. (HINT: You can use the cross product or the magnitude and right-hand-rule. If you use the magnitude and RHR, be sure to calculate the magnitude and angle of the velocity first) (b) This force will provide a centripal force on the particle and cause it to circle (or orbit) around the field lines. What would be the radius of this circular path? (c) What is the period of the orbit?

Chapter 40 Solutions

Fundamentals of Physics, Volume 1, Chapter 1-20

Ch. 40 - Prob. 11QCh. 40 - Prob. 12QCh. 40 - Prob. 13QCh. 40 - Prob. 14QCh. 40 - Prob. 1PCh. 40 - Prob. 2PCh. 40 - Prob. 3PCh. 40 - Prob. 4PCh. 40 - Prob. 5PCh. 40 - Prob. 6PCh. 40 - Prob. 7PCh. 40 - Prob. 8PCh. 40 - Prob. 9PCh. 40 - Prob. 10PCh. 40 - Prob. 11PCh. 40 - Prob. 12PCh. 40 - SSM What is the acceleration of a silver atom as...Ch. 40 - Prob. 14PCh. 40 - Prob. 15PCh. 40 - Assume that in the SternGerlach experiment as...Ch. 40 - Prob. 17PCh. 40 - Prob. 18PCh. 40 - Prob. 19PCh. 40 - Prob. 20PCh. 40 - Prob. 21PCh. 40 - Prob. 22PCh. 40 - Prob. 23PCh. 40 - Prob. 24PCh. 40 - Prob. 25PCh. 40 - Prob. 26PCh. 40 - Prob. 27PCh. 40 - Show that the number of states with the same...Ch. 40 - Prob. 29PCh. 40 - For a helium atom in its ground state, what are...Ch. 40 - Prob. 31PCh. 40 - Prob. 32PCh. 40 - Prob. 33PCh. 40 - Prob. 34PCh. 40 - Prob. 35PCh. 40 - Prob. 36PCh. 40 - Prob. 37PCh. 40 - Prob. 38PCh. 40 - Prob. 39PCh. 40 - Prob. 40PCh. 40 - Prob. 41PCh. 40 - Prob. 42PCh. 40 - Prob. 43PCh. 40 - Prob. 44PCh. 40 - Prob. 45PCh. 40 - Prob. 46PCh. 40 - Prob. 47PCh. 40 - Prob. 48PCh. 40 - Prob. 49PCh. 40 - Prob. 50PCh. 40 - Prob. 51PCh. 40 - Prob. 52PCh. 40 - Prob. 53PCh. 40 - Prob. 54PCh. 40 - Prob. 55PCh. 40 - Prob. 56PCh. 40 - Prob. 57PCh. 40 - Prob. 58PCh. 40 - Prob. 59PCh. 40 - Prob. 60PCh. 40 - Prob. 61PCh. 40 - Prob. 62PCh. 40 - Prob. 63PCh. 40 - Prob. 64PCh. 40 - Prob. 65PCh. 40 - Prob. 66PCh. 40 - Prob. 67PCh. 40 - Prob. 68PCh. 40 - Prob. 69PCh. 40 - Prob. 70PCh. 40 - Prob. 71PCh. 40 - Prob. 72PCh. 40 - Prob. 73PCh. 40 - Prob. 74PCh. 40 - Prob. 75PCh. 40 - Prob. 76PCh. 40 - Prob. 77PCh. 40 - Prob. 78PCh. 40 - Prob. 79P
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