Physics for Science and Engineering With Modern Physics, VI - Student Study Guide
4th Edition
ISBN: 9780132273244
Author: Doug Giancoli
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 40, Problem 6P
To determine
Find the conversion factor in going from kcal per mole to eV per molecule and binding energy of KCl in kcal per mole.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
What mass of phosphorus is needed to dope 1.0 g of silicon so that the number density of conduction electrons in the silicon is increased by a multiply factor of 106 from the 10^16 m-3 in pure silicon.
Pure silicon is used as a photon detector. An incoming photon can strike the surface and excite electrons from the valence band to the conduction band, where they can be counted.
(a) Compute the number of electrons you would expect to count if a silicon detector is struck with a 1.04-MeV gamma ray produced in the decay of a 136Cs nucleus.
(b) Explain why the counting of electrons should be more precise if the detector is cooled well below room temperature.
(Electroplating)
A steel part with surface area A = 130 cm² is to be tin-plated. What average plating thickness will result if 15 amps are applied for 10 min in an acid sulfate electrolyte bath? The cathode efficiency for tin is E = 90% and the plating constant C = 4.21 x 10-2 mm³/amp-s.
V = CIt
V = ECIt
d =
V
A
Typical cathode efficiencies in electroplating and values of plating constant C.
Compiled from [18].
Plate Metal Electrolyte
Cadmium (2) Cyanide
Chromium (3) Chromium-acid-sulfate
Copper (1)
Gold (1)
Nickel (2)
Silver (1)
Tin (4)
Zinc (2)
Cyanide
Cyanide
Acid sulfate
Cyanide
Acid sulfate
Chloride
Plating Constant ca
Cathode Efficiency % mm³/amp-s (in³/amp-min)
6.73 × 10-²
(2.47 × 10-4)
X
2.50 × 10-2
(0.92 × 10-4)
7.35 x 10-2
10.6 x 10-²
3.42 x 10-2
(2.69 × 10-4)
(3.87 × 10-4)
(1.25 × 10-4)
10.7 x 10-2
(3.90 × 10-4)
4.21 x 10-2
(1.54 × 10-4)
4.75 × 10-2
(1.74 x 10-4)
90
15
98
80
95
100
90
95
¹Most common valence given in parentheses (); this is the value assumed in determining…
Chapter 40 Solutions
Physics for Science and Engineering With Modern Physics, VI - Student Study Guide
Ch. 40.4 - Determine the three lowest rotational energy...Ch. 40.6 - Prob. 1BECh. 40.6 - Prob. 1CECh. 40.8 - Prob. 1DECh. 40 - What type of bond would you expect for (a) the N2...Ch. 40 - Describe how the molecule CaCl2 could be formed.Ch. 40 - Does the H2 molecule have a permanent dipole...Ch. 40 - Although the molecule H3 is not stable, the ion...Ch. 40 - The energy of a molecule can be divided into four...Ch. 40 - Would you expect the molecule H2+ to be stable? If...
Ch. 40 - Explain why the carbon atom (Z = 6) usually forms...Ch. 40 - Prob. 8QCh. 40 - Prob. 9QCh. 40 - Prob. 10QCh. 40 - Prob. 11QCh. 40 - Prob. 12QCh. 40 - Prob. 13QCh. 40 - Prob. 14QCh. 40 - Prob. 15QCh. 40 - Prob. 16QCh. 40 - Prob. 17QCh. 40 - Prob. 18QCh. 40 - Prob. 19QCh. 40 - Prob. 20QCh. 40 - Prob. 21QCh. 40 - Prob. 22QCh. 40 - Prob. 23QCh. 40 - Prob. 1PCh. 40 - (II) The measured binding energy of KCl is 4.43eV....Ch. 40 - (II) Estimate the binding energy of the H2...Ch. 40 - (II) The equilibrium distance r0 between two atoms...Ch. 40 - Prob. 5PCh. 40 - Prob. 6PCh. 40 - (III) (a) Apply reasoning similar to that in the...Ch. 40 - (I) Show that the quantity 2/I has units of...Ch. 40 - Prob. 9PCh. 40 - Prob. 10PCh. 40 - Prob. 11PCh. 40 - Prob. 12PCh. 40 - Prob. 13PCh. 40 - Prob. 14PCh. 40 - Prob. 15PCh. 40 - Prob. 16PCh. 40 - (II) Calculate the bond length for the NaCl...Ch. 40 - Prob. 18PCh. 40 - Prob. 19PCh. 40 - Prob. 20PCh. 40 - Prob. 21PCh. 40 - Prob. 22PCh. 40 - Prob. 23PCh. 40 - Prob. 24PCh. 40 - Prob. 25PCh. 40 - Prob. 26PCh. 40 - Prob. 27PCh. 40 - Prob. 28PCh. 40 - Prob. 29PCh. 40 - Prob. 30PCh. 40 - Prob. 31PCh. 40 - Prob. 32PCh. 40 - Prob. 33PCh. 40 - Prob. 34PCh. 40 - Prob. 35PCh. 40 - Prob. 36PCh. 40 - Prob. 37PCh. 40 - Prob. 38PCh. 40 - Prob. 39PCh. 40 - Prob. 40PCh. 40 - Prob. 41PCh. 40 - Prob. 42PCh. 40 - Prob. 43PCh. 40 - Prob. 44PCh. 40 - Prob. 45PCh. 40 - Prob. 46PCh. 40 - Prob. 47PCh. 40 - Prob. 48PCh. 40 - Prob. 49PCh. 40 - Prob. 50PCh. 40 - Prob. 51PCh. 40 - Prob. 52PCh. 40 - Prob. 53PCh. 40 - Prob. 54PCh. 40 - Prob. 55PCh. 40 - Prob. 56PCh. 40 - Prob. 57PCh. 40 - Prob. 58PCh. 40 - Prob. 59PCh. 40 - Prob. 60PCh. 40 - Prob. 61PCh. 40 - Prob. 62GPCh. 40 - Prob. 63GPCh. 40 - Prob. 64GPCh. 40 - Prob. 65GPCh. 40 - Prob. 66GPCh. 40 - Prob. 67GPCh. 40 - Prob. 68GPCh. 40 - Prob. 69GPCh. 40 - Prob. 70GPCh. 40 - Prob. 71GPCh. 40 - Prob. 72GPCh. 40 - Prob. 73GPCh. 40 - Prob. 74GPCh. 40 - Prob. 75GPCh. 40 - Prob. 76GPCh. 40 - Prob. 77GPCh. 40 - Prob. 78GPCh. 40 - Prob. 79GPCh. 40 - Prob. 80GPCh. 40 - Prob. 81GPCh. 40 - Prob. 82GPCh. 40 - Prob. 83GPCh. 40 - Prob. 84GPCh. 40 - Prob. 85GPCh. 40 - Prob. 86GPCh. 40 - Prob. 87GPCh. 40 - Prob. 88GPCh. 40 - Prob. 89GP
Knowledge Booster
Similar questions
- Silicon atoms with a concentration of 7x 1010 cm3 are added to gallium arsenide GaAs at T = 400 K. Assume that the silicon atoms act as fully ionized dopant atoms and that 15% of the concentration added replaces gallium atoms to free electrons and 85% replaces arsenic to create holes. Use the following parameters for GaAs at T = 300 K: N. = 4.7 x 1017 cm-3 and N, = 7 x 101cm-3. The bandgap is E, = 1.42 eV and it is constant over the temperature range. The donor concentration?arrow_forwardSilicon atoms with a concentration of 7× 1010 cm3 are added to gallium arsenide GaAs at T = 400 K. Assume that the silicon atoms act as fully ionized dopant atoms and that 15% of the concentration added replaces gallium atoms to free electrons and 85% replaces arsenic to create holes. Use the following parameters for GaAs at T= 300 K: N. = 4.7 x 1017cm-3 and N, = 7 x 1018cm-3. The bandgap is E, = 1.42 eV and it is constant over the temperature range. The acceptor concentration?arrow_forwardSilicon atoms with a concentration of 7x 1010 cm are added to gallium arsenide GaAs at T = 400 K. Assume that the silicon atoms act as fully ionized dopant atoms and that 15% of the concentration added replaces gallium atoms to free electrons and 85% replaces arsenic to create holes. Use the following parameters for GaAs at T = 300 K: N. = 4.7 x 1017cm-3 and N, = 7 x 1018 cm-3. The bandgap is E, = 1.42 eV and it is constant over the temperature range. The intrinsic concentration?arrow_forward
- (c) Calculate the Fermi energy of silver from the data given below: atom. Density of Silver = 10.5 gm/cm³ atomic weight = 108 h = 6.62×10-34 Joule - sec m = 9.1×10-³1 Kg. Avogadro's number =6.02×10-21 atoms/gm-arrow_forwardIn solid KCI the smallest distance between the centers of a. potassium ion and a chloride ion is 314 pm. Calculate the length of the edge of the unit cell and the density of KCI, assuming it has the same structure as sodium chloride.arrow_forwardGggarrow_forward
- B/ A new semiconductor material is to be n-type and doped with 6x10¹ cm³ donor atoms. Assume complete ionization and assume N,= 0. The effective density of states functions are N, =1.&r 10¹ cm and N,= 1.2x10 cm³ at 7-300 K. A special semiconductor device fabricated with this material requires that the electron concentration be no greater than 6.08x10¹ cm³ at 7= 400 K. What is the minimum band gap energy required in this new material?arrow_forward(1) for A, C & D 3RD SIGNIICANCE BUT FOR B, EXACT NO TOLERANCE. ANSWER ALSO E PLSarrow_forwardCheck Your Understanding The recommended daily amount of vitamin B3 or niacin, C6NH5 O2, for women who are not pregnant or nursing, is 14 mg. Find the number of molecule of niacin in that amount.arrow_forward
- Check Your Understanding If a=3+4i , what is the product a* a?arrow_forwarda) If the electron concentration increase along the x-axis of a conductor as shown in equation below: n=3-1030x2+2- 102x+1026 And D=1.2 x 10-4 m/s. Find the diffusion current at x =Smm? b) Find the minimum electron concentration nmin in semiconductor?arrow_forward(c) A common emitter BJT circuit and its voltage transfer curve is shown in Fig. 1(c) respectively. Assume the transistor common-emitter current gain, ß = 50, VBE (on) = 0.7 V, Rg = 100 kn and Rc = 1 k2. (i) Determine the input voltage at the point x. (ii) Calculate the base current, Ig and collector current, Ic at the point x. +Vcc Vo(V) Rc 5- Vo RB V, oww -RAR- IB VBE 0.5 V,(V) 15 Fig. 1(c) -END OF QUESTION-arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax