Fundamentals of Physics, Volume 1, Chapter 1-20
10th Edition
ISBN: 9781118233764
Author: David Halliday
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 41, Problem 51P
To determine
To verify:
that the electrons in copper at Fermi energy have a corresponding Fermi speed of 1600 km/s.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The Fermi energy of copper is 7.0 eV. Verify that the corresponding Fermi speed is 1600 km/s.
The Fermi energy of aluminum is 11.6 eV; its density and molar mass are 2.70 g/cm3 and 27.0 g/mol, respectively. From these data, determine the number of conduction electrons per atom.
At low temperatures, copper has a free-electron concentration n = 8.45 *1028 m-3. Using the free-electron model, find the Fermi energy for solid copper, and find the speed of an electron with a kinetic energy equal to the Fermi energy.
Chapter 41 Solutions
Fundamentals of Physics, Volume 1, Chapter 1-20
Ch. 41 - Prob. 1QCh. 41 - Prob. 2QCh. 41 - Prob. 3QCh. 41 - Prob. 4QCh. 41 - Prob. 5QCh. 41 - Prob. 6QCh. 41 - Prob. 7QCh. 41 - Prob. 8QCh. 41 - Prob. 9QCh. 41 - Prob. 10Q
Ch. 41 - Prob. 11QCh. 41 - Prob. 1PCh. 41 - Prob. 2PCh. 41 - Prob. 3PCh. 41 - Prob. 4PCh. 41 - Prob. 5PCh. 41 - Prob. 6PCh. 41 - Prob. 7PCh. 41 - Prob. 8PCh. 41 - Prob. 9PCh. 41 - Prob. 10PCh. 41 - Prob. 11PCh. 41 - Prob. 12PCh. 41 - Prob. 13PCh. 41 - Prob. 14PCh. 41 - Prob. 15PCh. 41 - Prob. 16PCh. 41 - Prob. 17PCh. 41 - Prob. 18PCh. 41 - Prob. 19PCh. 41 - Prob. 20PCh. 41 - Prob. 21PCh. 41 - Prob. 22PCh. 41 - Prob. 23PCh. 41 - Prob. 24PCh. 41 - Prob. 25PCh. 41 - Prob. 26PCh. 41 - Prob. 27PCh. 41 - Prob. 28PCh. 41 - Prob. 29PCh. 41 - Prob. 30PCh. 41 - Prob. 31PCh. 41 - Prob. 32PCh. 41 - Prob. 33PCh. 41 - Prob. 34PCh. 41 - Prob. 35PCh. 41 - Prob. 36PCh. 41 - Prob. 37PCh. 41 - Prob. 38PCh. 41 - Prob. 39PCh. 41 - Prob. 40PCh. 41 - Prob. 41PCh. 41 - Prob. 42PCh. 41 - Prob. 43PCh. 41 - Prob. 44PCh. 41 - Prob. 45PCh. 41 - Prob. 46PCh. 41 - Prob. 47PCh. 41 - Prob. 48PCh. 41 - Prob. 49PCh. 41 - Prob. 50PCh. 41 - Prob. 51PCh. 41 - Prob. 52PCh. 41 - Prob. 53P
Knowledge Booster
Similar questions
- Silver contains 5.8 * 1028 free electrons per cubic meter. At absolute zero, what is the Fermi energy (in J and eV) of silver?arrow_forwardThe Fermi energy of silver is µF = 5.51 eV. a) Calculate µ(7) of Ag at T = 400 and 4000 K. b) What is the rms speed of electrons at 0 K? What is the Fermi velocity? c) Plot the Fermi function at 0 and 4000 K in one graph and discuss the differences.arrow_forwardThe Fermi energy is the highest energy of an electron at 0k.At what temperature can we expect a 10% probability that the electrons in silver have an energy that is 2% above the Fermi energy of 5.5eV?arrow_forward
- The Fermi energy is the highest energy of an electron at 0K. At what temperature can we expect a 10% probability that the electrons in silver have an energy that is 1% above the Fermi energy of 5.5 eV?arrow_forwardThe Fermi energy of sodium is 3.23 eV. (a) Find the average energy Eav of the electrons at absolute zero. (b) What is the speed of an electron that has energy Eav ? (c) At what Kelvin temperature T is kT equal to EF ? (This is called the Fermi temperature for the metal. It is approximately the temperature at which molecules in a classical ideal gas would have the same kinetic energy as the fastest-moving electron in the metal.)arrow_forwardThe density of sodium metal at room temperature is 0.95 g/cm³. Assuming that there is one conduction electron per sodium atom, calculate the Fermi energy and Fermi tempera- ture of sodium.arrow_forward
- Since the Fermi energy level of zinc is EF = 9.47 eV, what is the number of electrons per unit energy per unit volume at this energy level? Since the resistivity of zinc is 5.90 x 10^-8 ohm.m, calculate the average time interval between collisions of electrons.arrow_forwardGold has an atomic mass of 197 u, a density of 19.3 x 10^3 kg/m^3, a Fermi energy of 5.54 eV, and a resistivity of 2.04 x 10^-8 ohms. Estimate the mean free path in atom spacings between collisions of the free electrons in gold under the assumption that each gold atom contributes one electron to the electron gas.arrow_forwardThe average energy of an electron in a specific metal at 0 K is 2.9 eV. Calculate the value of the Fermi energy in a specific metal. (A) 5.51 eV (В) 2.44 eV (С) 4.83 eV (D) 2.83 eVarrow_forward
- A certain bivalent metal has a density of 6.906 g/cm3 and a molar mass of 97.8 g/mol. Calculate (a) the number density of conduction electrons, (b) the Fermi energy, (c) the Fermi speed, and (d) the de Broglie wavelength corresponding to this electron speed.arrow_forwardSilver contains 5.8 * 1028 free electrons per cubic meter. At absolute zero, what is the density of states (in states>J and states>eV) at the Fermi energy for a block of silver of volume 1.0 cm3?arrow_forwardCalculate the copper's mean free path. Let's say copper has a Fermi energy of 6.65 eV. 9.21 x1028 m-3 of electrons are present per unit volume. In copper, an electron has an effective mass of 1.51 times its rest mass. Copper has 5.9x107 S/m in conductivity.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning