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Two parametric equation are given by:
In one figure, make plots of y versus x and v versus u for
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Chapter 5 Solutions
EBK MATLAB: AN INTRODUCTION WITH APPLIC
- The phasor of the impedance of an AC circuit has no vertical component. What does this mean? there are no reactive components in the AC circuit the resistance of the circuit is equal to the reactance of the reactive components the inductive reactance and capacitive reactance are equal in magnitude there are no inductors in the circuitarrow_forwardOne steradian represents .... .... ... (rad)^2 O degree O 2rad (rad)3 Oarrow_forwardwrite the phasor equivalentsarrow_forward
- For the circuit shown below, determine: Amplitude of the Voltage Source RMS value of the Voltage Source Frequency of the Voltage Source Phase Angle of the Voltage Source Total Resistance Total Inductance Total Capacitance Inductive Reactance Capacitive Reactance Total Impedance in Polar Form Total Current in Polar Form Voltage across the Resistor Voltage across the Inductance Voltage across the Capacitor Draw all voltages and current on the Complex Plane show all the workarrow_forwardThe following is given for a series R-L-C circuit: resistor (R) = 8 Ohms, an inductor (L) = 32 mH and a capacitor (C) = 800uF. The circuit is supplied by a voltage source of e = 120 sin (125t) Volts. What is the angular frequency of the ac source? What is the period of ac source? What is the circuit impedance? What is the power factor? What is the real power of the circuit? What is the rms value of the circuit current?arrow_forwardI) Convert the following phasors to the time domain if the frequency is I KHz. . h-3 A a) k- 12 /40 b)arrow_forward
- 1. What impedance vector 0 – j22 represents:A. A pure resistance.B. A pure inductance.C. A pure capacitance.D. An inductance combined with a resistance.arrow_forwardPower factor 90 to 100% 88 to <90% 85 to <88% 80 to <85% 75 to < 80% 70 to < 75% 65 to < 70% 60 to <65% 55 to <60% 50 to <55% Less than 50% Surcharge None 2% 4% 9% 16% 24% 34% 44% 57% 72% 80% Use the table given for the following. A house with inductive loads has an avg consumption of 40kW and 26kVAR is supplied 230 Vrms source. We want to make the surcharge 0% by adding a capacitor. a. What is the smallest kVar of the capacitor that would reduce the surcharge to 0%?arrow_forwardMinistry of Manpower Directorate General of Technological Education Salalah College of Technology Zlectrical Inginearina Problem - 8 Refer to the circuit below and -25V C2 N. compute the following: i) Total capacitance ii) Voltage across C, iii)Charge across C, iv)Voltage across C5 5 uF C1 5 uF 5 uF C4 5 uF C6 5 uF -16-65V. C5 5 uF (Take V, as 25V) 8-35V VT 25Varrow_forward
- Given: L1 = 17 mHL2 = 21 mHL3 = 0.014 HL4 = 11981 mHL5 = 89 uH Calculate the total inductance of the circuit, LT.arrow_forwardConsider a sinusoidal emf source, v(t) = Vm sin (@t) results of current of i(t) = Im sin (@t+0) is applied to circuit of R, L & C in series. How to find the voltage across each one?.arrow_forwardAn electrical circuit with a sinusoidal voltage source, a resistor, and a capacitor all connected in series. The voltage across the capacitor: Select one: a. Leads the current in the capacitor by exactly 90o b. Is in phase with the sinusoidal voltage source c. Is in phase with the voltage across the resistor d. Leads the current in the circuit by 90o e. Lags the current in the circuit by 90oarrow_forward
- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning
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