The balanced chemical equation has to be written for the combustion of glucose (C 6 H 12 O) . Concept introduction: Balancing reaction: Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side. Steps in balancing the information Step 1: Write the unbalanced equation Step 2: Find the coefficient to balance the equation. The coefficient should be reduced to the smallest whole number.

Question

85. Propane, C3H8, is a hydrocarbon that is commonly used as a fuel. (a) Write a balanced equation for the complete combustion of propane gas. (b) Calculate the volume of air at 25 °C and 1.00 atmosphere that is needed to completely combust 25.0 grams of propane. Assume that air is 21.0 percent O2 by volume. (Hint: We will see how to do this calculation in a later chapter on gases—for now use the information that 1.00 L of air at 25 °C and 1.00 atm contains 0.275 g of O2 per liter.) (c) The heat of combustion of propane is −2,219.2 kJ/mol. Calculate the heat of formation, ΔH∘fΔHf° of propane given that ΔH∘fΔHf° of H2O(l) = −285.8 kJ/mol and ΔH∘fΔHf° of CO2(g) = −393.5 kJ/mol. (d) Assuming that all of the heat released in burning 25.0 grams of propane is transferred to 4.00 kilograms of water, calculate the increase in temperature of the water.

Answer 1

Question

Chapter 5, Problem 32Q

(a)

Interpretation Introduction

Interpretation:

The balanced chemical equation has to be written for the combustion of glucose (C6H12O).

Concept introduction:

Balancing reaction:

Balanced reaction is a chemical reaction in which number of atoms for each element in the reaction and the total charge are same on both reactant side and the product side.

Steps in balancing the information

Step 1: Write the unbalanced equation

Step 2: Find the coefficient to balance the equation.

The coefficient should be reduced to the smallest whole number.

(b)

Interpretation Introduction

Interpretation:

The explanation has to be given for the burning wood is essentially the same as that of metabolizing glucose.

Concept introduction:

Combustion reaction:

Combustion is an exothermic reaction between a fuel (the reductant) and an oxidant. Oxidant is usually atmospheric oxygen.

Generally organic molecule undergoes combustion reaction which produces carbon dioxide and water molecule.

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85. Propane, C3H8, is a hydrocarbon that is commonly used as a fuel. (a) Write a balanced equation for the complete combustion of propane gas. (b) Calculate the volume of air at 25 °C and 1.00 atmosphere that is needed to completely combust 25.0 grams of propane. Assume that air is 21.0 percent O2 by volume. (Hint: We will see how to do this calculation in a later chapter on gases—for now use the information that 1.00 L of air at 25 °C and 1.00 atm contains 0.275 g of O2 per liter.) (c) The heat of combustion of propane is −2,219.2 kJ/mol. Calculate the heat of formation, ΔH∘fΔHf° of propane given that ΔH∘fΔHf° of H2O(l) = −285.8 kJ/mol and ΔH∘fΔHf° of CO2(g) = −393.5 kJ/mol. (d) Assuming that all of the heat released in burning 25.0 grams of propane is transferred to 4.00 kilograms of water, calculate the increase in temperature of the water.

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