Chapter 5, Problem 50P

When the Moon is directly overhead at sunset, the force by Earth on the Moon $F_{\text{EM}}$ , is essentially at $90°$ to the force by the Sun on the Moon, $F_{\text{SM}}$, as shown below. Given that $F_{\text{EM}}=1.98\times {10}^{2\text{0}}\text{ N}$ and $F_{\text{SM}}=4.36\times {10}^{2\text{0}}\text{ N}$ , all other forces on the Moon are negligible, and the mass of the Moon is $7.35\times {10}^{2\text{2}}\text{ kg}$, determine the magnitude of the Moon’s acceleration.