Concept explainers
For a given surface, the electric flux,
C. Sketch vector
Learn your wayIncludes step-by-step video
Chapter 5 Solutions
Tutorials in Introductory Physics
Additional Science Textbook Solutions
Essential University Physics (3rd Edition)
The Cosmic Perspective
Physics for Scientists and Engineers with Modern Physics
Applied Physics (11th Edition)
Sears And Zemansky's University Physics With Modern Physics
- The nonuniform charge density of a solid insulating sphere of radius R is given by = cr2 (r R), where c is a positive constant and r is the radial distance from the center of the sphere. For a spherical shell of radius r and thickness dr, the volume element dV = 4r2dr. a. What is the magnitude of the electric field outside the sphere (r R)? b. What is the magnitude of the electric field inside the sphere (r R)?arrow_forwardA dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure 124.63. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and is given by E = (3.00 + 2.00x2)i N/C, where x is in meters. (a) Calculate the net electric flux leaving the closed surface. (b) What net charge enclosed by the surface?arrow_forwardA square surface of area 9 cm2 is in a space of uniform electric field of magnitude 104 N/C . The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux (in N · m2/C) through the square, when the normal to it makes the following angles with the electric field. Note that these angles can also be given as 180° + θ. a. 36degrees b. 90 degrees c. 0 degreesarrow_forward
- Consider the uniform electric field E = (3.0ĵ + 7.0) ✕ 103 N/C. (a) What is its electric flux (in N · m2/C) through a circular area of radius 2.3 m that lies in the yz-plane? (Enter the magnitude.) (b) What is its electric flux (in N · m2/C) through a circular area of radius 2.3 m that lies 45.0° above the xy-plane? (Assume that the unit normal vector is n̂ = 1/(2)1/2(î+k). )arrow_forwardAn electric field is found to be <3xyz, 2x2/z, x+y+z>. What is the x-component of the electric field vector at position (2, 6, 1)m?arrow_forwardA solid insulating sphere of radius 0.07 m carries a total charge of 25 µC. Concentric with this sphere is a conducting spherical shell of inner radius 0.12 m and outer radius of 0.18 m and carrying a total charge of -54 µC. Find (a) the charge distribution for the insulating sphere and the conducting spherical shell, and the magnitude of the electric field at the following distances from the center of the two spheres and shell: (b) 0.05 m, (c) 0.10 m, (d) 0.15 m, and (e) 0.25 m.arrow_forward
- A circular surface with a radius of 0.062 m is exposed to a uniform electric field of magnitude 1.58 × 104 N/C. The electric flux through the surface is 68 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?arrow_forwardElectric Flux and Gauss’s Law show solution A circular plane whose r=2.2m is placed in an electric field E=800N/C. The electric field makes an angle of 20 ͦwith the plane. Solve for the magnitude of the electric flux through the plane. A square plane with each side s=1m is placed in an electric field E=800N/C. The electric field makes an angle of 90 ͦwith the plane. Solve for the magnitude of the electric flux through the plane. Solve for the electric flux through a 3D closed surface enclosing a chargearrow_forwardAn infinitely long solid insulating cylinder of radius R has a uniform volume charge density of 0.99μC/m3. If the magnitude of the electric field 0.302m from the axis of the cylinder is 3880N/C, what is R, the radius of the cylinder, in meters? Assume that R<0.302m, so the point of observation is exterior to the cylinder.arrow_forward
- A square surface with sides of 2 m × 2m is located over the xy-plane, where a constant electric field with a magnitude of 150 Nm^2/C^2 is present. The direction of the electric field vector is parallel with the surface. What is the total electric flux present in the surface?* A) 37.5 Nm^2/C B) 75 Nm^2/C C) 300 Nm^2/C D) 600 Nm^2/Carrow_forwardA square surface of area 2.3 cm2 is in a space of uniform electric field of magnitude 1800 NC. The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux through the square, when the normal to it makes the following angles with the electric field. Note that these angles can also be given as 180°+θ. (a) 30° (b) 90° (c) 0°arrow_forwardA flat surface with an area of 1.25 m² is rotated through a uniform horizontal electric field of 5 N/C. What is the electric flux if the normal of the surface is (a.) perpendicular to the electric field, (b.) parallel to the electric field and (c.) forms a 32° between the electric field?arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning