Chapter 5.3, Problem 22E

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Chapter
Section

### Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

# In Exercises 17 to 24, complete each proof.Given: D G D E = D H D F Prove: ∠ D G H ≅ ∠ E PROOF Statements Reasons 1. ?2. ∠ D ≅ ∠ D 3. Δ D G H ∼ Δ D E F 4. ? 1. ?2. ?3. ?4. ?

To determine

To prove:

The statement DGHE if the proportions are given DGDE=DHDF.

Explanation

Definition:

SASâˆ¼:

If an angle of one triangle is congruent to an angle of a second triangle and the pairs of sides including the angles are proportional (in length), then the triangles are similar.

CASTC:

Corresponding angles of similar triangles are congruent.

Description:

Given that DGDE=DHDF.

The given figure is shown below.

Figure

From the given figure, it is observed that DGDE=DHDF are the pairs of corresponding sides which are proportional and also noticed that the common point of both triangles is D.

Hence, by identity âˆ Dâ‰…âˆ D.

The above mentioned SASâˆ¼ definition, the two triangles DGH and DEF are similar since an angle of one triangle is congruent to an angle of a second triangle and the pairs of sides including the angles are proportional (in length)

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