   Chapter 5.1, Problem 43E Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085

Solutions

Chapter
Section Elementary Geometry For College St...

7th Edition
Alexander + 2 others
ISBN: 9781337614085
Textbook Problem

In the figure, assume that a > 0. Prove that B D ⋅ D E ≠ B E ⋅ A C . To determine

To prove:

BDDEBEAC.

Explanation

It is given, BD = a, DE = 5, BE = a + 4 and AC = a + 1.

Substitute BD = a and DE = 5 in BDDE.

BDDE=5a     .....(1)

Substitute BE = a + 4 and AC = a + 1 in BEAC.

BEAC=(a+4)(a+1)

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