Organic Chemistry: A Guided Inquiry
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN: 9780618974122
Author: Andrei Straumanis
Publisher: Cengage Learning
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Chapter 6, Problem 12E

(a)

Interpretation Introduction

Interpretation:

The structure of six carbon alkene that is drawn with one ring and one double bond to be drawn with no rings.

Concept Introduction:

The structure of six carbon alkene is drawn as a ring wherein the hydrocarbon is mostly depicted as ring. Isomers are those compounds which have similar formula but different arrangement of their atoms.

(b)

Interpretation Introduction

Interpretation:

The given statement needs to be explained.

Concept Introduction:

When the compound is represented using chemical symbols of its individual elements having numeric subscripts indicating the number of atoms, it is said to be molecular formula.

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Several factors can affect alkene stability. Explain why alkene A is more stable than alkene B even though both contain disubstituted carbon–carbon double bonds.
for part b)why do we write AlCl3 at top of the arrow and AlCl4 at the bottom of arrow??is it any connection between the two?does it means that AlCl 4 need to be present in order to make AlCl3 reacts to the molecule and make the reaction to process??   2. why when AlCl3 added,Cl was removed from the ring?what princeiple theory is that ?   2. when SO3 is added ,SO3 attached to the ring,why ?what principle is behind this phenamonane   3.Just confused about why AlCl3 removes Cl from the ring,while HSO3 donate SO3 to the ring. Is it Something about nucleohilic or eletrciohillic?
Consider the tricyclic structure B. (a) Label each substituent on the rings as axial or equatorial. (b) Draw B using chair conformations for each six-membered ring. (c) Label the atoms on the ring fusions (the carbons that join each set of two rings together) as cis or trans to each other.

Chapter 6 Solutions

Organic Chemistry: A Guided Inquiry

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