Chapter 6, Problem 6A.2E

(a)

Interpretation Introduction

Interpretation:

Conjugate acid of ${\text{C}}_{\text{2}}{\text{O}}_{\text{4}}{}^{2-}$ has to be written.

Concept Introduction:

Generally acid donates proton to form conjugate base.  As donation of proton takes place, the conjugate base will have fewer hydrogen ions than that is present in acid.  Base accepts protons to form conjugate acid.  As proton is accepted, the conjugate acid will have more hydrogen ions than that of the base from which it is formed.

(b)

Interpretation Introduction

Interpretation:

Conjugate acid of ${\text{C}}_{\text{6}}{\text{H}}_{\text{5}}{\text{NH}}_{\text{2}}$ has to be written.

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

Conjugate acid of ${\text{NH}}_{\text{2}}\text{OH}$ has to be written.

Concept Introduction:

Refer part (a).

(d)

Interpretation Introduction

Interpretation:

Conjugate base of ${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}$ has to be given.

Concept Introduction:

Refer part (a).

(e)

Interpretation Introduction

Interpretation:

Conjugate base of ${\text{HNO}}_{\text{2}}$ has to be given.

Concept Introduction:

Refer part (a).

(f)

Interpretation Introduction

Interpretation:

Conjugate base of ${\text{HCrO}}_{\text{4}}{}^{-}$ has to be given.

Concept Introduction:

Refer part (a).