Chapter 6.1, Problem 56SR

a)

To determine

To represent: The change in the height of an object in free fall in the 430 foot shaft.

Answer to Problem 56SR

Change in height by the object will be represented by a negative integer $-430$

Explanation of Solution

Given information: To stimulate space travel, NASA uses 430-foot shaft and an object takes 5 second in a free fall while covering this 430 foot shaft.

Concept used: As object is coming down from space, it means it’s a decrease in its initial value ,so the total change in its height will be represented by a negative integer. And it is used unitary method, to get covering distance in one second, in which 430 is divided by 5.

Calculation: As in 5 seconds, objects covers 430 foot .

So, total distance covered in one second $\frac{430}{5}=86$ feet.

Conclusion: It is concluded that change in height by the object will be represented by a negative integer $-430$ .

b)

To determine

To find: How far the object travel in one second, on average.

Answer to Problem 56SR

Total distance covered by object in one second is 86 feet.

Explanation of Solution

Given information: To stimulate space travel, NASA uses 430-foot shaft and an object takes 5 second in a free fall while covering this 430 foot shaft.

Concept used: As object is coming down from space, it means it’s a decrease in its initial value ,so the total change in its height will be represented by a negative integer. And it is used unitary method, to get covering distance in one second, in which 430 is divided by 5.

Calculation: As in 5 seconds, objects covers 430 foot .

So, total distance covered in one second $\frac{430}{5}=86$ feet.

Conclusion: It is concluded that change total distance covered by object in one second is 86 feet.