   # A piece of chocolate cake contains about 400 calories. A nutritional calorie is equal to 1000 calories (thermochemical calories), which is equal to 4.184 kJ. How many 8-in-high steps must a 180-lb man climb to expend the 400 Cal from the piece of cake? See Exercise 28 for the formula for potential energy. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 7, Problem 130CP
Textbook Problem
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## A piece of chocolate cake contains about 400 calories. A nutritional calorie is equal to 1000 calories (thermochemical calories), which is equal to 4.184 kJ. How many 8-in-high steps must a 180-lb man climb to expend the 400 Cal from the piece of cake? See Exercise 28 for the formula for potential energy.

Interpretation Introduction

Interpretation:

The chocolate cake piece required steps climb should be calculated.

Concept Introduction:

• Potential energy is the energy of an object due to position of it. For the gravitational potential energy is,

Equation:

PEgrav = mass × g × height......(1)

### Explanation of Solution

Explanation

Energy of a chocolate cake piece is 400Cal  (4.184 kJ)

High of chocolate cake piece is 8 inch

Weight of a man is 180lb

The given energy and height of a chocolate cake piece and weight of a man are recorded as shown above.

To calculate the energy of cake in kJ .

1000 calories of thermo chemical calories' equal to 4.184 kJ

=400kcal×4.18kJkcal=1.7×103kJ

=2.0×103kJ=2.0×106kJ

• The given values are substitute in above equation to give the energy of cake in kJ .
• The energy of piece of cake is 2.0×106J .

To calculate the required energy for go up to 1 step

PE=(180lb×1kg2

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