Consider a balloon filled with helium at the following conditions. 313 g He 1.00 atm 1910. L Molar Heat Capacity = 20.8 J/°C mol The temperature of this balloon is decreased by 41.6°C as the volume decreases to 1643 L, with the pressure remaining constant. Determine q, w, and ∆ E( in KJ ) for the compression of the balloon.

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Interpretation Introduction Interpretation: The heat, work and internal energy change of the given balloon should be calculated. Concept Introduction: Internal energy is a total energy of a system, consists of kinetic, potential energies. The internal energy change is associate with heat flow or as work done on or by a system. Equation: ΔE=q ± w ...... (1) q is a heat w is a work The work is considered as a pressure and volume for the gases expansion and compressions in thermodynamic process. Formula: Explanation Explanation Record the given data: Mass of He is 313 g Pressure is 1 .0 atm Initial volume is 1910 L . Molar heat capacity of He is 20 .8 J/°C .mol Final volume is 1643 L Decreased temperature is 41 .6°C The given mass of He, pressure, volumes molar heat capacity and decreased temperature are recorded as shown above. To calculate the mole of given H e gas. =Mass of He (g)× 1 mol of He Mass He (g) =313 g× 1Mole He 4 .003 g He = 78 .2 mol The given values are plugging in above equation to give mole of 313g of H e . The mole of 313g of H e is 78 .2 mol . To calculate the absorbed heat of H e balloon. Absorbed heat ( J ) = Molar heat capacity ( J ) /Temperature change ( c ) ×mass ofsubstance ( g ) absorbed heat (q ) = 20 .8 J °C mol ×78 .2 mol×(-41

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Chemistry: An Atoms First Approach

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Steven S. Zumdahl + 1 other

Publisher: Cengage Learning

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Chemistry: An Atoms First Approach

2nd Edition

Steven S. Zumdahl + 1 other

Publisher: Cengage Learning

ISBN: 9781305079243

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Interpretation Introduction

Interpretation: The heat, work and internal energy change of the given balloon should be calculated.

Concept Introduction: Internal energy is a total energy of a system, consists of kinetic, potential energies. The internal energy change is associate with heat flow or as work done on or by a system.

Equation:

ΔE=q±w......(1)

q is a heat

w is a work

The work is considered as a pressure and volume for the gases expansion and compressions in thermodynamic process.
Formula:

Explanation of Solution

Explanation

Record the given data:

Mass of He is 313 gPressure is 1.0 atmInitial volume is 1910 L.Molar heat capacity of He is 20.8 J/°C.molFinal volume is 1643 LDecreased temperature is 41.6°C

The given mass of He, pressure, volumes molar heat capacity and decreased temperature are recorded as shown above.

To calculate the mole of given He gas.

=Mass of He (g)×1 mol of HeMass He (g)=313 g×1Mole He4.003 g He= 78.2 mol

The given values are plugging in above equation to give mole of 313g of He.
The mole of 313g of He is 78.2 mol.

To calculate the absorbed heat of He balloon.

Absorbed heat (J) = Molar heat capacity(J) /Temperature change(c)×mass ofsubstance (g)

absorbed heat (q ) = 20.8 J°C mol×78.2 mol×(-41

Chemistry: An Atoms First Approach

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Chemistry: An Atoms First Approach

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