The reason of lone pair occupying at equatorial position should be described. Concept introduction: The electrons involved in bond formation for any compound are known as bond pair and the electrons remained unused in bonding are known as lone pairs. As per the VSEPR theory, any molecule should have minimum energy and minimum repulsion states. It means that, the bonds should be arranged in such manner which could minimize the electronic repulsion and stabilize the molecules. Further, the axial positions are the positions parallel to the axes and the equitorial positions are perpendicular to the axes and lie on the equator.
The reason of lone pair occupying at equatorial position should be described. Concept introduction: The electrons involved in bond formation for any compound are known as bond pair and the electrons remained unused in bonding are known as lone pairs. As per the VSEPR theory, any molecule should have minimum energy and minimum repulsion states. It means that, the bonds should be arranged in such manner which could minimize the electronic repulsion and stabilize the molecules. Further, the axial positions are the positions parallel to the axes and the equitorial positions are perpendicular to the axes and lie on the equator.
Solution Summary: The author explains that the lone pair is positioned at equatorial position rather than axial position, to minimize the electronic repulsion and stabilize the molecules.
Table 2 Molecules with Multiple Bonds
Molecule
CH2O
HCN
CO2
CO
[NO2]-
Number of Bond Pairs
Number of Lone Pairs
Number of Electron Domains
Molecular Geometry (Shape)
Bond Angle
Polar or Non-Polar
) Bean hexene is an odor compound used in cosmetics and cleaners. It is also known as leguminal. Its formula is:
CH3CH2CHCHCH2CH2OCHCH2CH3
|
OCH3
Please draw a Lewis structure for this compound with CORRECT GEOMETRY (use dashes and wedges!)
Label all pi bonds in the molecule (if there are any)
Indicate the bond angles for the red highlighted section of the molecule. (hint: you may want to keep the main carbon chain in-plane with the page for clarity)
For this question, you don’t need to draw out the orbitals.
Why is water bent while Carbon dioxide is linear? Explain using the Lewis Representation
Chapter 7 Solutions
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