An Introduction to Thermal Physics
1st Edition
ISBN: 9780201380279
Author: Daniel V. Schroeder
Publisher: Addison Wesley
expand_more
expand_more
format_list_bulleted
Question
Chapter 7.3, Problem 33P
(a)
To determine
The reason why in the first approximation model, the chemical potential must always lie precisely in the middle of the gap.
(b)
To determine
The expression for the number of
(c)
To determine
The number of conduction electrons in the cubic centimeter of Silicon at room temperature and the comparison between conduction electrons of Silicon and of Copper.
(d)
To determine
The reason why semiconductor conducts electricity better at higher temperature.
Expert Solution & Answer
Trending nowThis is a popular solution!
Learn your wayIncludes step-by-step video
schedule07:09
Students have asked these similar questions
Consider a free Fermi gas in two dimensions, confined to a squarearea A = L2.
Find the Fermi energy (in terms of N and A), and show that the average energy of the particles is €F /2.
Discuss the failure and Success of Classical free electron theory? Differentiate between Conductor, Insulator and Semiconductor on the basis of Conduction and valence band?
In a solid, consider the energy level lying 0.4eV below Fermi level.What is Probability of this level not being occupied by an electron at the room temperature?
Chapter 7 Solutions
An Introduction to Thermal Physics
Ch. 7.1 - Prob. 1PCh. 7.1 - Prob. 3PCh. 7.1 - Prob. 4PCh. 7.1 - Show that when a system is in thermal and...Ch. 7.1 - Prob. 7PCh. 7.2 - Prob. 8PCh. 7.2 - Prob. 9PCh. 7.2 - Prob. 11PCh. 7.2 - Prob. 12PCh. 7.2 - Prob. 13P
Ch. 7.2 - Prob. 14PCh. 7.2 - Prob. 15PCh. 7.2 - Prob. 16PCh. 7.2 - Prob. 17PCh. 7.2 - Prob. 18PCh. 7.3 - Prob. 19PCh. 7.3 - Prob. 20PCh. 7.3 - Prob. 21PCh. 7.3 - Prob. 22PCh. 7.3 - Prob. 24PCh. 7.3 - Prob. 25PCh. 7.3 - Prob. 26PCh. 7.3 - Prob. 29PCh. 7.3 - Prob. 32PCh. 7.3 - Prob. 33PCh. 7.3 - Prob. 34PCh. 7.4 - Prob. 37PCh. 7.4 - Prob. 38PCh. 7.4 - Prob. 39PCh. 7.4 - Prob. 40PCh. 7.4 - Prob. 41PCh. 7.4 - Prob. 42PCh. 7.4 - Prob. 43PCh. 7.4 - Prob. 44PCh. 7.4 - Prob. 45PCh. 7.4 - Prob. 46PCh. 7.4 - Prob. 47PCh. 7.4 - Prob. 48PCh. 7.4 - Prob. 49PCh. 7.4 - Prob. 50PCh. 7.4 - Prob. 51PCh. 7.4 - Prob. 52PCh. 7.4 - Prob. 53PCh. 7.4 - Prob. 54PCh. 7.4 - Prob. 55PCh. 7.4 - Prob. 56PCh. 7.5 - Prob. 57PCh. 7.5 - Prob. 58PCh. 7.5 - Prob. 59PCh. 7.5 - Prob. 60PCh. 7.5 - The heat capacity of liquid 4He below 0.6 K is...Ch. 7.5 - Prob. 62PCh. 7.5 - Prob. 63PCh. 7.5 - Prob. 64PCh. 7.6 - Prob. 65PCh. 7.6 - Prob. 66PCh. 7.6 - Prob. 67PCh. 7.6 - Prob. 68PCh. 7.6 - If you have a computer system that can do...Ch. 7.6 - Prob. 70PCh. 7.6 - Prob. 71PCh. 7.6 - Prob. 72PCh. 7.6 - Prob. 73PCh. 7.6 - Prob. 75P
Knowledge Booster
Similar questions
- Consider a system consisting of a single hydrogen atom/ion, which has two possible states: unoccupied (i.e., no electron present) and occupied (i.e., one electron present, in the ground state). Calculate the ratio of the probabilities of these two states, to obtain the Saha equation, already derived. Treat the electrons as a monatomic ideal gas, for the purpose of determining J-l. Neglect the fact that an electron has two independent spin states.arrow_forwardFor a solid metal having a Fermi energy of 8.500 eV, what is the probability, at room temperature, that a state having an energy of 8.520 eV is occupied by an electron?arrow_forwardIf the energy gap for an insulating material is 4.5 eV, what is the probability that an electron will be promoted to the conduction band when the temperature is 100 °C? You may assume that the Fermi energy is in the middle of the energy gap.arrow_forward
- What is the probability that, at a temperature of T = 300 K, an electron will jump across the energy gap Eg (= 5.5 eV) in a diamond that has a mass equal to the mass of Earth? Use the molar mass of carbon in Appendix F; assume that in diamond there is one valence electron per carbon atom.arrow_forwardIs it reasonable to expect superconductivity in a "glass," a material with almost no crystalline structure? Why or why not, if that's the case?arrow_forwardTo obtain a more clearly defined picture of the FermiDirac distribution, consider a system of 20 FermiDirac particles sharing 94 units of energy. By drawing diagrams like Figure P10.11, show that there are nine different microstates. Using Equation 10.2, calculate and plot the average number of particles in each energy level from 0 to 14E. Locate the Fermi energy at 0 K on your plot from the fact that electrons at 0 K fill all the levels consecutively up to the Fermi energy. (At 0 K the system no longer has 94 units of energy, but has the minimum amount of 90E.) 1 Microstate8 others? One of the nine equally probable microstates for 20 FD particles with a total energy of 94E.arrow_forward
- What is the number of occupied states in the energy range of 0.0300 eV that is centered at a height of 6.10 eV in the valenceband if the sample volume is 5.00 * 10-8 m3, the Fermi level is 5.00 eV, and the temperature is 1500 K?arrow_forwardCalculate the mismatch stress in a thin epitaxial film of Ge on a Si (110) substrate. Both Si and Ge have cubic lattice structures with lattice constants 0.5431 nm and 0.5657 nm, respectively.arrow_forwardLet f (e) be the Fermi Dirac distribution function and U be the chemical potential. Obtain the expression for derivative of f (e) with respect to e at e=uarrow_forward
- What is the probability that a state 0.0620 eV above the Fermi energy will be occupied at (a) T= 0 K and (b) T =320 K?arrow_forwardShow that the entropy of a two-state paramagnet, expressed asa function of temperature, is S = Nk [ln(2coshx) -x tanh x], where x = µB/kT.Check that this formula has the expected behavior as T → 0 and T → ∞ .arrow_forwardThe intensities of spectroscopic transitions between the vibrational states of a molecule are proportional to the square of the integral ∫ψv′xψvdx over all space. Use the relations between Hermite polynomials given in Table 7E.1 to show that the only permitted transitions are those for which v′ = v ± 1 and evaluate the integral in these cases.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill