Chapter 8.2, Problem 8.29E

To determine

To calculate how many different license plates were possible in $1959$ and $1999$ if there are no restrictions on the letters and numbers used in any position.

Answer to Problem 8.29E

For $1959$ : $17576000$

For $1999$ : $45697600$

Explanation of Solution

For $1959$ : Use multiplication counting principle and that there are $26$ letters and ten numbers:

  $26\times 26\times 26\times 10\times 10\times 10=17576000$

For $1999$ : Use multiplication counting principle and that there are $26$ letters and ten numbers:

  $26\times 26\times 26\times 10\times 10\times 26=45697600$