Glencoe Physics: Principles and Problems, Student Edition
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN: 9780078807213
Author: Paul W. Zitzewitz
Publisher: Glencoe/McGraw-Hill
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Chapter 9, Problem 96A

(a)

To determine

To sketch:The situations before and after collision.

(a)

Expert Solution
Check Mark

Answer to Problem 96A

The sketch of the situations before and after collision is shown in Figure 1.

Explanation of Solution

Given info:

Consider the mass of fullback as mA=92kg and the mass of line backers are mB=mC=75 kg .

Consider the initial velocity towards a goal line for a touchdown is vAi=5m/s .

The initial velocity of one line backer vBi=2.0m/s .

The initial velocity of other line backer vCi=4.0m/s

Calculation:

For the given specifications, the situation before and after collision are shown below.

  Glencoe Physics: Principles and Problems, Student Edition, Chapter 9, Problem 96A

Figure 1

A full back is running towards the positive x-direction, with a velocity vAi while two line-backers are running towards negative x-direction, with a velocity vBi and vCi respectively.

Conclusion:

Therefore, the sketch of the situations before and after collision is shown in the figure 1.

(b)

To determine

The velocity of the players after collision.

(b)

Expert Solution
Check Mark

Answer to Problem 96A

The velocity of the players after collision is vf=0.041 m/s .

Explanation of Solution

Given:

Consider the mass of fullback as mA=92kg and the mass of line backers are mB=mC=75 kg .

Consider the initial velocity towards a goal line for a touchdown is vAi=5m/s .

The initial velocity of one line backer vBi=2.0m/s .

The initial velocity of other line backer vCi=4.0m/s

Formula used:

The expression for the momentum is,

  p=mv

Here, m is the mass of the system and v is the velocity of the system.

Calculation:

Consider the final velocity of the fullback and the line bakers are vAf=vBf=vCf=vf .

Refer to Figure 1 given in part (a).

By the law of conservation of momentum, the initial momentum of the system is equal to the final momentum of the system.

  pi=pfpAi+pBi+pCi=pAf+pBf+pCfmAvAi+mBvBi+mCvCi=mAvAf+mBvBf+mCvCfmAvAi+mBvBi+mCvCi=(mA+mB+mC)vf

  mAvAi+mBvBi+mCvCi(mA+mB+mC)=vfvf=(92 kg×5m/s)+(75 kg×(2m/s))+(75 kg×(4m/s))(92 kg)+(75 kg)+(75 kg)vf=10242vf=0.041m/s

Conclusion:

Therefore, the velocity of the players after collision is vf=0.041 m/s .

(c)

To determine

To identify:Whether the fullback scores a touchdown.

(c)

Expert Solution
Check Mark

Answer to Problem 96A

Yes, the fullback scores a touchdown.

Explanation of Solution

Given:

Consider the mass of fullback as mA=92kg and the mass of line backers are mB=mC=75 kg .

Consider the initial velocity towards a goal line for a touchdown is vAi=5m/s .

The initial velocity of one line backer vBi=2.0m/s .

The initial velocity of other line baker vCi=4.0m/s

Formula used:

The expression for the momentum is,

  p=mv

Here, m is the mass of the system and v is the velocity of the system.

Calculation:

From part (b), the velocity of the players after collision is vf=0.041 m/s .

The velocity of the players after collision is positive. This shows that the velocity of the players is in the direction of the fullback. So the fullback scores a touchdown.

Hence, the fullback can cross the goal line for a touchdown.

Conclusion:

Therefore, the fullback scores a touchdown.

Chapter 9 Solutions

Glencoe Physics: Principles and Problems, Student Edition

Ch. 9.1 - Prob. 11SSCCh. 9.1 - Prob. 12SSCCh. 9.1 - Prob. 13SSCCh. 9.1 - Prob. 14SSCCh. 9.1 - Prob. 15SSCCh. 9.1 - Prob. 16SSCCh. 9.2 - Prob. 17PPCh. 9.2 - Prob. 18PPCh. 9.2 - Prob. 19PPCh. 9.2 - Prob. 20PPCh. 9.2 - Prob. 21PPCh. 9.2 - Prob. 22PPCh. 9.2 - Prob. 23PPCh. 9.2 - Prob. 24PPCh. 9.2 - Prob. 25PPCh. 9.2 - Prob. 26PPCh. 9.2 - Prob. 27PPCh. 9.2 - Prob. 28PPCh. 9.2 - Prob. 29PPCh. 9.2 - Prob. 30SSCCh. 9.2 - Prob. 31SSCCh. 9.2 - Prob. 32SSCCh. 9.2 - Prob. 33SSCCh. 9.2 - Prob. 34SSCCh. 9.2 - Prob. 35SSCCh. 9 - Prob. 36ACh. 9 - Prob. 37ACh. 9 - Prob. 38ACh. 9 - Prob. 39ACh. 9 - Prob. 40ACh. 9 - Prob. 41ACh. 9 - Prob. 42ACh. 9 - Prob. 43ACh. 9 - Prob. 44ACh. 9 - Prob. 45ACh. 9 - Prob. 46ACh. 9 - Prob. 47ACh. 9 - Prob. 48ACh. 9 - Prob. 49ACh. 9 - Prob. 50ACh. 9 - Prob. 51ACh. 9 - Prob. 52ACh. 9 - Prob. 53ACh. 9 - Prob. 54ACh. 9 - Prob. 55ACh. 9 - Prob. 56ACh. 9 - Prob. 57ACh. 9 - Prob. 58ACh. 9 - Prob. 59ACh. 9 - Prob. 60ACh. 9 - Prob. 61ACh. 9 - Prob. 62ACh. 9 - Prob. 63ACh. 9 - Prob. 64ACh. 9 - Prob. 65ACh. 9 - Prob. 66ACh. 9 - Prob. 67ACh. 9 - Prob. 68ACh. 9 - Prob. 69ACh. 9 - Prob. 70ACh. 9 - Prob. 71ACh. 9 - Prob. 72ACh. 9 - Prob. 73ACh. 9 - Prob. 74ACh. 9 - Prob. 75ACh. 9 - Prob. 76ACh. 9 - Prob. 77ACh. 9 - Prob. 78ACh. 9 - Prob. 79ACh. 9 - Prob. 80ACh. 9 - Prob. 81ACh. 9 - Prob. 82ACh. 9 - Prob. 83ACh. 9 - Prob. 84ACh. 9 - Prob. 85ACh. 9 - Prob. 86ACh. 9 - Prob. 87ACh. 9 - Prob. 88ACh. 9 - Prob. 89ACh. 9 - Prob. 90ACh. 9 - Prob. 91ACh. 9 - Prob. 92ACh. 9 - Prob. 93ACh. 9 - Prob. 94ACh. 9 - Prob. 95ACh. 9 - Prob. 96ACh. 9 - Prob. 97ACh. 9 - Prob. 98ACh. 9 - Prob. 99ACh. 9 - Prob. 100ACh. 9 - Prob. 101ACh. 9 - Prob. 1STPCh. 9 - Prob. 2STPCh. 9 - Prob. 3STPCh. 9 - Prob. 4STPCh. 9 - Prob. 5STPCh. 9 - Prob. 6STPCh. 9 - Prob. 7STPCh. 9 - Prob. 8STPCh. 9 - Prob. 9STP
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