WORLD OF CELL+MASTERING ACCESS >CUSTOM
9th Edition
ISBN: 9781323445044
Author: Hardin
Publisher: PEARSON C
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Chapter 9, Problem 9.7PS
Propionate Fermentation. Although lactate and ethanol are the best-known products of fermentation, other pathways are also known, some with important commercial applications. Swiss cheese production, for example, depends on the bacterium Propionibacterium freudenreichii, which converts pyruvate to propionate (CH3—CH2—COO−). Fermentation of glucose to propionate always generates at least one other product as well.
- (a) Why is it not possible to devise a scheme for the fermentation of glucose with propionate as the sole end-product?
- (b) Suggest an overall scheme for propionate production that generates only one additional product, and indicate what that product might be.
- (c) If you know that Swiss cheese production actually requires both propionate and carbon dioxide and that both are produced by Propionibacterium fermentation, what else can you now say about the fermentation process that this bacterium carries out?
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Chapter 9 Solutions
WORLD OF CELL+MASTERING ACCESS >CUSTOM
Ch. 9 - How are catabolic and anabolic pathways similar?...Ch. 9 - Prob. 9.2CCCh. 9 - Why do oxidation and reduction reactions always...Ch. 9 - How can glucose be oxidized in the absence of...Ch. 9 - In the absence of oxygen, why is it necessary to...Ch. 9 - Prob. 9.6CCCh. 9 - Prob. 1QCh. 9 - Why dont glycolysis (glucose to pyruvate) and...Ch. 9 - Why are the key regulatory enzymes in glycolysis...Ch. 9 - Why do cancer cells carry out high rates of...
Ch. 9 - High-Energy Bonds. When first introduced by Fritz...Ch. 9 - The History of Glycolysis. Following are several...Ch. 9 - Glycolysis in 25 Words or Fewer. Complete each of...Ch. 9 - Energetics of Carbohydrate Utilization. The...Ch. 9 - QUANTITATIVE Glucose Phosphorylation. The direct...Ch. 9 - Ethanol Intoxication and Methanol Toxicity. The...Ch. 9 - Propionate Fermentation. Although lactate and...Ch. 9 - QUANTITATIVE Glycolysis and Gluconeogenesis. As...Ch. 9 - Prob. 9.9PSCh. 9 - Youve Got Some Explaining to Do. Explain each of...Ch. 9 - Arsenate Poisoning. Arsenate (HAsO42) is a potent...Ch. 9 - Life Without Phosphofructokinase. Many bacteria do...Ch. 9 - Prob. 9.13PS
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- True or False? Intermediates in the glycolysis pathway can be a source of raw material if the cell wants to construct biological molecules such as triglycerides or amino acids, but the citric acid cycle cannot be used this way.arrow_forward"Anaerobic glycolysis" (the conversion of glucose all the way to two lactate molecules) results in no net production of NADH. True or False- whyarrow_forwardStarch Hydrolysis: Suppose you could selectively prevent production of α-amylase or oligo 1,6 glucosidase in an organism that normally hydrolysis starch. Which enzyme would the organism miss the most?arrow_forward
- A violation of the First Law? The complete combustion of glucose to CO 2 and H 2 O yields 30 ATP, as shown in Table 18.4 . However, the synthesis of glucose requires only 18 ATP. How is it possible that glucose synthesis from CO 2 and H 2 O requires only 18 ATP , but combustion to CO 2 and H 2 O yields 30 ATP? Is it a violation of the First Law of Thermodynamics , or perhaps a miracle?arrow_forwardSaccharides: Using the following substrates, estimate the net ATP yield after glycolytic pathway, Kreb’s cycle and electron transport chain. Assume that the estimate for ATP yield per mole of NADH is 3 moles of ATP, while 1 mole of FADH2 is equivalent to 2 moles of ATP, and one mole of GTP is equivalent to one mole of ATP. Show all pertinent solutions and determine: a) ATP used, b) ATP produced, and c) Net ATP. Based on your solutions, rank the substrates based on increasing yield of ATP 1. Three moles of glucose-6-phosphatearrow_forwardSaccharides: Using the following substrates, estimate the net ATP yield after glycolytic pathway, Kreb’s cycle and electron transport chain. Assume that the estimate for ATP yield per mole of NADH is 3 moles of ATP, while 1 mole of FADH2 is equivalent to 2 moles of ATP, and one mole of GTP is equivalent to one mole of ATP. Show all pertinent solutions and determine: a) ATP used, b) ATP produced, and c) Net ATP. Based on your solutions, rank the substrates based on increasing yield of ATP 1. Three moles of glucose-6-phosphate 2. Four moles of pyruvic acidarrow_forward
- Understanding the Oxidation of Glucose and Its Products in the TCA Cycle Glycolysis, the pyruvate dehydrogenase reaction, and the TCA cycle result in complete oxidation of a molecule of glucose to CO2. Review the calculation of oxidation numbers for individual atoms in any molecule, and then calculate the oxidation numbers of the carbons of glucose, pyruvate, the acetyl carbons of acetyl-CoA. and the metabolites of the TCA cycle to convince yourself that complete oxidation of glucose involves removal of 24 electrons and that each acetyl-CoA through the TCA cycle gives up 8 electrons.arrow_forwardStructure, function, Oxidative decarboxylation of pyruvate reactions and mechanisms of activity regulation of pyruvatedehydrogenase multi-enzyme complex.arrow_forward
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