Concept explainers
a.
To compare area of squares
a.
Answer to Problem 8.4.3P
2s+1 is change in area.
Explanation of Solution
Given:
Side of sqaure1=
Side of sqaure2=
Calculation:
Area of square=(side)2
Area of square1=
Area of square2=
Solving using identity
So,
Change in area=area of square2- Area of square1
=
=2s+1 Hence, 2s+1 is change in area.
b.
To compare area of squares
b.
Answer to Problem 8.4.3P
2s +3 is change in area.
Explanation of Solution
Given:
Side of sqaure1=
Side of sqaure2=
Calculation:
Area of square=(side)2
Area of square1=
Solving using identity
So,
Area of square2=
Solving using identity
So,
change in area=area of square2- Area of square1
=
= 2s +3 Hence, 2s +3 is change in area.
c.
To compare area of squares
c.
Answer to Problem 8.4.3P
2s +5 is change in area.
Explanation of Solution
Given:
Side of sqaure1=
Side of sqaure2=
Calculation:
Area of square2=
Solving using identity
So,
Area of square2=
Solving using identity
So,
Change in area=area of square2- Area of square1
=
Solving,
= 2s +5 Hence, 2s +5 is change in area.
d.
To find how much the area.
d.
Answer to Problem 8.4.3P
The area will be will 2a +1
Explanation of Solution
Given:
Side1= a
Side2= a +1
Calculation:
Based on parts above, the change in the area will be
The change of area= 2a +1.
Chapter ISG Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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