Chapter U5.110, Problem 6E

Interpretation Introduction

Interpretation: Which one is not a redox reaction needs to be explained.

Concept Introduction: Whenever an atom or ion loses electrons, other atom gains electrons. The loss of electrons is known as oxidation, and the gain of electrons is known as reduction. Oxidation and reduction always occur together. This process is known as oxidation-reduction or redox.

Answer to Problem 6E

The reaction $\text{Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right){\text{+CuSO}}_{\text{4}}\left(\text{aq}\right)\to {\text{BaSO}}_{\text{4}}\left(\text{s}\right)\text{+Cu}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right)$ is not a redox reaction.

Explanation of Solution

The net ionic equation for the reaction is as follows:

  $\begin{array}{l}{\text{Ba}}^{2+}\left(\text{aq}\right)+2{\text{NO}}_{\text{3}}{}^{-}\left(\text{aq}\right){\text{+Cu}}^{2+}\left(\text{aq}\right){\text{+SO}}_{\text{4}}{}^{2-}\left(\text{aq}\right)\to {\text{BaSO}}_{\text{4}}\left(\text{s}\right){\text{+Cu}}^{2+}\left(\text{aq}\right)+2{\text{NO}}_{\text{3}}{}^{-}\left(\text{aq}\right)\end{array}$

  $\begin{array}{c}{\text{Ba}}^{2+}\left(\text{aq}\right)+{\text{SO}}_{\text{4}}{}^{2-}\left(\text{aq}\right)\to {\text{BaSO}}_{\text{4}}\left(\text{s}\right)\end{array}$

All element has same electron on both reactant and product side. Therefore, there is no acceptation and donation of electrons. Since, in redox reaction both oxidation and reduction takes place. Hence, this reaction is not a redox reaction.

Conclusion

The reaction $\text{Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right){\text{+CuSO}}_{\text{4}}\left(\text{aq}\right)\to {\text{BaSO}}_{\text{4}}\left(\text{s}\right)\text{+Cu}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(\text{aq}\right)$ is not a redox reaction.