. The human gene for ß2 lens crystallin has the components listed below. The numbers represent nucleotidepairs that make up the particular component. Assumefor simplicity that no alternative splicing is involved.5′ UTR 1741st exon 1191st intron 5322nd exon 3372nd intron 14313rd exon 2083rd intron 3804th exon 4444th intron 995th exon 5463′ UTR 715Answer the following questions about the ß2 lenscrystallin gene, primary transcript, and gene product.Questions asking where should be answered with oneof the 11 components from the list or with None.Assume poly-A tails contain 150 As.a. How large is the ß2 lens crystallin gene in bp (basepairs)?b. How large is the primary transcript for ß2 lenscrystallin in bases?c. How large is the mature mRNA for ß2 lens crystallin in bases?d. Where would you find the base pairs encoding theinitiation codon?e. Where would you find the base pairs encoding thestop codon?f. Where would you find the base pairs encoding the5′ cap?g. Where would you find the base pairs that constitutethe promoter?h. Which intron interrupts the 3′ UTR?i. Where would you find the sequences encoding theC terminus?j. Where would you find the sequence encoding thepoly-A tail?k. How large is the coding region of the gene in bp(base pairs)?l. How many amino acids are in the ß2 lens crystallinprotein?m.Which intron interrupts a codon?n. Which intron is located between codons?o. Where would you be likely to find the site specifyingpoly-A addition?You find in lens-forming cells from several differentpeople small amounts of a polypeptide that has thesame N terminus as the normal ß lens crystallin, but ithas a different C terminus. The polypeptide is114 amino acids long, of which 94 are shared with the normal protein and 20 are unrelated junk. No mutation is involved in the production of this 114-aminoacid protein.p. Outline a hypothesis for the process that wouldproduce this protein. Your hypothesis should explain why 94 amino acids are the same as in thenormal ß2 lens crystallin.q. Explain why you would expect that a polypeptidesuch as the 114-mer described above would on average have 20 amino acids of junk.
. The human gene for ß2 lens crystallin has the components listed below. The numbers represent nucleotide
pairs that make up the particular component. Assume
for simplicity that no alternative splicing is involved.
5′ UTR 174
1st exon 119
1st intron 532
2nd exon 337
2nd intron 1431
3rd exon 208
3rd intron 380
4th exon 444
4th intron 99
5th exon 546
3′ UTR 715
Answer the following questions about the ß2 lens
crystallin gene, primary transcript, and gene product.
Questions asking where should be answered with one
of the 11 components from the list or with None.
Assume poly-A tails contain 150 As.
a. How large is the ß2 lens crystallin gene in bp (base
pairs)?
b. How large is the primary transcript for ß2 lens
crystallin in bases?
c. How large is the mature mRNA for ß2 lens crystallin in bases?
d. Where would you find the base pairs encoding the
initiation codon?
e. Where would you find the base pairs encoding the
stop codon?
f. Where would you find the base pairs encoding the
5′ cap?
g. Where would you find the base pairs that constitute
the promoter?
h. Which intron interrupts the 3′ UTR?
i. Where would you find the sequences encoding the
C terminus?
j. Where would you find the sequence encoding the
poly-A tail?
k. How large is the coding region of the gene in bp
(base pairs)?
l. How many amino acids are in the ß2 lens crystallin
protein?
m.Which intron interrupts a codon?
n. Which intron is located between codons?
o. Where would you be likely to find the site specifying
poly-A addition?
You find in lens-forming cells from several different
people small amounts of a polypeptide that has the
same N terminus as the normal ß lens crystallin, but it
has a different C terminus. The polypeptide is
114 amino acids long, of which 94 are shared with the normal protein and 20 are unrelated junk. No mutation is involved in the production of this 114-amino
acid protein.
p. Outline a hypothesis for the process that would
produce this protein. Your hypothesis should explain why 94 amino acids are the same as in the
normal ß2 lens crystallin.
q. Explain why you would expect that a polypeptide
such as the 114-mer described above would on average have 20 amino acids of junk.
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