Question
Asked Oct 31, 2019
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106
Acid/Base Titrations
What is the molarity of a solution of phosphoric acid (a triprotic acid) if 10.00 mL of
the phosphoric acid solution require 37.11 mL of 0.3382 M NaOH solution to titrate
it?
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106 Acid/Base Titrations What is the molarity of a solution of phosphoric acid (a triprotic acid) if 10.00 mL of the phosphoric acid solution require 37.11 mL of 0.3382 M NaOH solution to titrate it?

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Expert Answer

Step 1

Given that,

Volume of Phosphoric acid is 10.0 mL

Volume of NaOH is 37.11mL

Molarity of the solution of NaOH is 0.3382M

Step 2

The chemical equation of phosphoric acid with NaOH is

3NaOH+Н,РО, a,PO, +3H,0
here,
V 10.0mL 0.01 0L
V 37.11mL-0.03 71 1L
М-%3?
М,-0.3382M
п, 31
п, 33
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3NaOH+Н,РО, a,PO, +3H,0 here, V 10.0mL 0.01 0L V 37.11mL-0.03 71 1L М-%3? М,-0.3382M п, 31 п, 33

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Step 3

Calculate the molarity by...

M,V
MV
M2Vzn
М
0.3382x0.03711x1
М
3x0.010
0.41835M
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M,V MV M2Vzn М 0.3382x0.03711x1 М 3x0.010 0.41835M

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