11.9 LAB: Simple integer division - multiple exception handlers Write a program that reads integers userNum and divNum as input, and output the quotient (userNum divided by divNum). Use a try block to perform the statements. Use a catch block to catch any ArithmeticException and output an exception message with the getMessage() method. Use another catch block to catch any InputMismatchException and output an exception message with the toString() method. Note: ArithmeticException is thrown when a division by zero happens. InputMismatchException is thrown when a user enters a value of different data type than what is defined in the program. Do not include code to throw any exception in the program. Ex: If the input of the program is: 15 3 the output of the program is: 5 Ex: If the input of the program is: 10 0 the output of the program is: Arithmetic Exception: / by zero Ex: If the input of the program is: 15.5 5 the output of the program is: Input Mismatch Exception: java.util. InputMismatchException

In this java program, please explain the code and the output of the program. Source Code: import java.util.Scanner; public class Main { public static void main(String[] args) {  Scanner scanner = new Scanner(System.in);  String name;  String department;  double baseSalary;  String joinedDate;   System.out.print("Enter the Name : ");  name = scanner.nextLine();   System.out.print("Enter the Department : ");  department = scanner.nextLine();   System.out.print("Enter the Joined Date : ");  joinedDate = scanner.nextLine();   System.out.print("Enter the Base Salary : ");  baseSalary = scanner.nextDouble();   StaffDeatils staff = new StaffDeatils(name, department, baseSalary, joinedDate);   System.out.println();  staff.toString();  }} class StaffDeatils { private String name; private String department; private double baseSalary; private String joinedDate;  public StaffDeatils(String name, String department, Double salary, String joinedDate) {  this.name = name;  this.department =…

import java.util.Scanner; public class CircleAndSphereWhileLoop{    public static final double MAX_RADIUS = 500.0;        public static void main(String[] args)    {        Scanner in = new Scanner(System.in);         // Step 2: Read a double value as radius using prompt         //         "Enter the radius (between 0.0 and 500.0, exclusive): "         // Step 3: While the input radius is not in the ragne (0.0, 500.0)        //            Display a message on one line (ssuming input value -1)        //               "The input number -1.00 is out of range."        //            Read a double value as radius using the same promt                 double circumference = 2 * Math.PI * radius;        double area = Math.PI * radius * radius;        double surfaceArea = 4 * Math.PI * Math.pow(radius, 2);        double volume = (4 / 3.0) * Math.PI * Math.pow(radius, 3);                // Step 4: Display the radius, circle circumference, circle area,        //         sphere surface area, and…

1. What is the output of the following program? import java.util.Scanner; public class Factorial { public static void main(String args[]){ Scanner scanner = new Scanner(System.in); System.out.printIn("Enter the number:"); scanner.nextInt(); int factorial = fact(num); System.out.println("Factorial of int num = entered number is: "+factorial); } static int fact(int n) { int output; if(n==1){ return 1; } output = fact(n-1)* n; return output; } }

Java - How to make this a horizontal statement with a newline. Whenever I use System.out.println, it makes the output vertical instead of horizontal. What am I doing wrong? Program below. import java.util.Scanner; public class LabProgram {   public static void main(String[] args) {      int i;      String InputString;            Scanner sc = new Scanner(System.in);            InputString = sc.nextLine();            char[] strArray = new char[InputString.length()];            for(i = 0; i < InputString.length(); i++){            strArray[i] = InputString.charAt(i);      }            for(i = 0 ; i< InputString.length() ; i++)            if(strArray[i] >= 'a' && strArray[i] <= 'z' || strArray[i] >= 'A' && strArray[i] <= 'Z')      System.out.print(strArray[i]); (the problem line)      }}

StringFun.java import java.util.Scanner; // Needed for the Scanner class 2 3 /** Add a class comment and @tags 4 5 */ 6 7 public class StringFun { /** * @param args not used 8 9 10 11 12 public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.print("Please enter your first name: "); 13 14 15 16 17 18 System.out.print("Please enter your last name: "); 19 20 21 //Output the welcome message with name 22 23 24 //Output the length of the name 25 26 27 //Output the username 28 29 30 //Output the initials 31 32 33 //Find and output the first name with switched characters 34 //All Done! } } 35 36 37

How do I code: public static void rotateElements(int[] arr, int rotationCount) public static void reverseArray(int[] arr) In Java?

I need help with this java problem described below:  import java.util.Scanner; import java.util.InputMismatchException;   public class ExpirationMonth {    public static void main(String[] args) {       Scanner scnr = new Scanner(System.in);       int expirationMonth;       boolean valueFound = false;              while (!valueFound) {          try {             expirationMonth = scnr.nextInt();             valueFound = true; System.out.println("Expiration month: " + expirationMonth); System.out.println("Processed one valid input value");          }            /* Your code goes here */         }    } }

I need help fixing this java program as shown below:   import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker {   public static void main(String[] args) {      Scanner scnr = new Scanner(System.in);       String inputName;      int age;            inputName = scnr.next();      while (!inputName.equals("-1")) {         // FIXME: The following line will throw an InputMismatchException.         //        Insert a try/catch statement to catch the exception.         age = scnr.nextInt();         System.out.println(inputName + " " + (age + 1));                  inputName = scnr.next();      }   }}

I need help with this Java Problem as described in the image below: import java.util.Scanner; public class LabProgram {      public static int fibonacci(int n) {      /* Type your code here. */         }      public static void main(String[] args) {      Scanner scnr = new Scanner(System.in);      int startNum;            startNum = scnr.nextInt();      System.out.println("fibonacci(" + startNum + ") is " + fibonacci(startNum));   }}