A GC separation was conducted on a sample containing a 14) pesticide analyte, Pymetozine. This sample was treated with an internal standard of chlorobenzene, giving a concentration of 15.0 ppm. A 1.0 uL injection onto the GC gave an FID response of 1012 for chlorobenzene and 3411 for Pymetozine. A 1.0 uL standard solution of 30.0 ppm chlorobenzene with 15.0 ppm of Pymetozine was injected giving response of 899 and 2791 respectively. What is the concentration of Pymetozine in the sample?

A GC separation was conducted on a sample containing a 14) pesticide analyte, Pymetozine. This sample was treated with an internal standard of chlorobenzene, giving a concentration of 15.0 ppm. A 1.0 uL injection onto the GC gave an FID response of 1012 for chlorobenzene and 3411 for Pymetozine. A 1.0 uL standard solution of 30.0 ppm chlorobenzene with 15.0 ppm of Pymetozine was injected giving response of 899 and 2791 respectively. What is the concentration of Pymetozine in the sample?

Macroscale and Microscale Organic Experiments

7th Edition

ISBN:9781305577190

Author:Kenneth L. Williamson, Katherine M. Masters

Publisher:Kenneth L. Williamson, Katherine M. Masters

Chapter8: Thin-layer Chromatography: Analyzing Analgesics And Isolating Lycopene From Tomato Paste

Section: Chapter Questions

Problem 10Q: A TLC plate showed two spots with Rf values of 0.25 and 0.26. The plate was removed from the...

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A TLC plate showed two spots with Rf values of 0.25 and 0.26. The plate was removed from the developing chamber, the residual solvent was allowed to evaporate from the plate, and then the plate was returned to the developing chamber. What would you expect to see after the second development was complete?
A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting solution was brought to pH 3 and extracted with two 5-mL portions of methyl isobutyl ketone containing the lead-complexing agent APCD. The extract was aspirated directly into an air/acetylene flame and yielded an absorbance of 0.527 at 283.3 nm. Five-milliliter aliquots of standard solutions containing 0.400 and 0.600 ppm of lead were treated in the same way and yielded absorbances of 0.396 and 0.599. Find the concentration of lead in the sample in ppm assuming that Beer’s law is followed.
A 5.00-mL sample of blood was treated with trichloroacetic acid to precipitate proteins. After centrifugation, the resulting solution was brought to pH 3 and extracted with two 5-mL portions of methyl isobutyl ketone containing the lead-complexing agent APCD. The extract was aspirated directly into an air/acetylene flame and yielded an absorbance of 0.569 at 283.3 nm. Five-milliliter aliquots of standard solutions containing 0.400 and 0.600 ppm of lead were treated in the same way and yielded absorbances of 0.396 and 0.599. Please calculate the concentration of lead in the sample in ppm.
A 0.0200 gram blood sample was decomposed by a microwave digestion technique followed by dilution to 100.0 mL in a volumetric flask. Aliquots of the sample solution were treated with a lead complexing reagent and water as follows: Solution 1: 10.0 ml blood sample + 20.0 mL complexing agent + 30.0 mL H20. Solution 2: 10.0 ml blood sample + 20.0 mL complexing agent + 26.0 mL H20 + 4.00 mL of 78 ppb Pb2+ standard. The resulting solutions were analyzed by UV/Vis at 375 nm. Absorbance for solution 1 = 0.155 and for solution 2 = 0.216. Calculate the concentration of lead (ppb) in the original sample.
A spectrophotometric method for the quantitative determination of the concentration ofPb2+ in blood yields an Ssamp of 0.133 for a 1 mL sample of blood that has been diluted to 6 mL. A second sample is spiked with 1 µL of a 1467 ppb Pb2+ standard and diluted to 6 mL, yielding an Sspike of 0.491. Determine the concentration of Pb2+ in the original sample of blood.
A brewed tea brand sample was subjected to solvent extraction to extract caffeine. The cup of tea measuring 200 mL was extracted with petroleum ether. With KD = 20.0 (caffeine in pet ether-water), the % caffeine (194.10) extracted after 3 extractions with a total of 75.0 mL pet ether used is: A. 97.7% B. 28.6% C. 71.4% D. 2.33%
A sample of anhydrous Na2CO3 (FM = 105.989) is suspected to be contaminated with eitherNaHCO3 (FM = 84.007) or NaOH (FM = 39.997) To verify the suspicion, a 0.7483 g sample was dissolved to prepare a 50.00 mL solution, and a 10.00 mL aliquot was taken to prepare a 100 mL solution, where 25.00 mL was analyzed using single flask method. If the sample requires 27.50 mL of standard 0.0125 N HCl to reach the phenolphthalein endpoint and another 28.40 mL to reach the bromcresol green endpoint, calculate the percentagecomposition (in %w/w) of all the basic components in the sample.
Pesticide residues were found in a lot of oranges; the compound identified was the epoxide of heptachlor (EH). To quantify the amount of this pesticide in oranges, 20 grams were taken from fruit peels and mixed with methylene chloride to extract it. The concentration of heptachlor epoxide in the sample was determined by gas chromatography coupled to a detector mass (GC-MS); and calibration was performed using anthracene (A) as internal standard. For In this analysis, the anthracene had a concentration of 350 ppm and the same volume was added to each standard. The table below shows the concentrations of the standard and the ratio of the areas.and the sample is: 0.1080.Determine the concentration of heptachlor epoxide in the sample.
20 tablets containing the dibasic drug ethambutol hydrochloride (MW 277.2 g/mol) were powdered. 0.3354 g of tablet powder was dissolved in 10 mL of 2 M sodium hydroxide and was extracted with 5 x 25 mL quantities of chloroform. The combined extracts were evaporated and the residue was dissolved in 100 mL of anhydrous acetic acid. Non-aqueous titration was carried out using 1-naphtholbenzein solution as indicator and 0.1014 M acetous perchloric acid. Volume of acetous perchloric acid required = 14.2 mL, weight of 20 tablets = 3.367 g, state content of ethambutol hydrochloride per tablet = 100 mg. Calculate the % of stated content in the tablets.
A sample of anhydrous Na2CO3 (FM = 105.989) is suspected to be contaminated with either NaHCO3 (FM = 84.007) or NaOH (FM = 39.997) To verify the suspicion, a 0.7483 g sample was dissolved to prepare a 50.00 mL solution, and a 10.00 mL aliquot was taken to prepare a 100 mL solution, where 25.00 mL was analyzed using single flask method. If the sample requires 27.50 mL of standard 0.0125 N HCl to reach the phenolphthalein endpoint and another 28.40 mL to reach the bromcresol green endpoint, calculate the percentage composition (in %w/w) of all the basic components in the sample.
The concentration of purified OXA-M290 is tested with a BCA assay. Serial dilutions of a bovine serum albumin (BSA) stock solution are prepared, then pipetted into a 96-well plate; each dilution of the BSA standard is tested in triplicate. Then, bicinchoninic acid and Cu2+ ions are added to all of the wells of the plate. After incubating the plate for 1 hour, a microplate reader is used to measure the absorbance of all of the wells in the plate at 560 nm. This generates the following data: BSA conc. (μg/mL), Replicate 1 Absorbance, Replicate 2 Absorbance, Replicate 3 Absorbance 40, 1.360, 1.403, 1.481 20, 0.750, 0.745, 0.810 10, 0.380, 0.344, 0.398 5, 0.198, 0.160, 0.183 2.5, 0.090, 0.100, 0.085 1.25, 0.038, 0.043, 0.051 0.625, 0.024, 0.028, 0.019 Prepare a calibration curve using these data. You can use Excel, R, SPSS or an equivalent graphing software. In this graph, plot absorbance (y-axis) against the concentration of the protein standard (x-axis). Calculate and plot…
A juice concentrate was colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the sample solution and various concentrations of the standard glucose solution were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbances at 480 nm for distilled water, glucose standard, and for the sample are 0.052, 1.702, and 0.926, respectively. What is the reducing sugar concentration (mg/mL) in the juice concentrate? The equation of the line was plotted to be: y = 1.6656x - 0.0885 0.578 mg/mL 577.9 mg/mL 57.7 mg/mL 5.78 mg/mL