A sample of pure water was spiked with 0.520 ng/mL silver ion. Ten replicate determinations of the spiked water sample gave0.530, 0.510, 0.487, 0.473, 0.514, 0.494, 0.498, 0.502. 0.480, and 0.465 ng/mL silver ion. Determine the mean percent recoveryof the spike and the detection limit of the analytical method used for the silver ion determination.mean percent recovery:detection limit:ng/mL

Given, Sample of pure water is spiked to =0.520ngmL

Answered: A sample of pure water was spiked with…

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter16: Data Processing With Excel

Section: Chapter Questions

Problem 5P

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The same chloride analysis but using a new method for which the standard deviation was not known, gave the following replicate results, mean and estimated standard deviation: Chloride (ppm) = 346, 359, 350; Mean = 351.67 ppm; Standard deviation = 6.66ppm. Solve for the CI for the 3 determinations at 95% probability level.
In the determination of ethanol concentration in alcoholic beverages using the GCFID method, why do we need to calculate the coefficient variation (CV). standard deviation, repeatability, response factor and response ratio? And how to calculate this parameter?
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A volume of 250 ml of a 0.05 M solution of a reagent of formula weight (relative molecular mass) 40 was made up, the weighing being done by difference. The standard deviation of each weighing was 0.0001 g: what were the standard deviation and relative standard deviation of the weight of reagent used? The standard deviation of the volume of solvent used was 0.05 ml. Express this as a relative standard deviation. Hence calculate the relative standard deviation of the molarity of the solution. Repeat the calculation for a reagent of formula weight 392.
A volume of 250 ml of a 0.05 M solution of a reagent of formula weight (relative molecular mass) 40 was made up, the weighing being done by difference. The standard deviation of each weighing was 0.0001 g. 1 (a) What were the standard deviation and relative standard deviation of the weight of reagent used?
A volume of 250 ml of a 0.05 M solution of a reagent of formula weight (relative molecular mass) 40 was made up, the weighing being done by difference. The standard deviation of each weighing was 0.0001 g. The standard deviation of the volume of solvent used was 0.05 ml. Express this as a relative standard deviation. Hence calculate the relative standard deviation of the molarity of the solution.
FT-IR technique can be utilized for the analysis of unknown analytes by matching it with__________. Both choices are correct Commercial library/database Reference standard
25 ml of pickled brine was taken from an apple pickled with vinegar and diluted to 500 ml, 25 ml of this was taken and acidity was determined with 0.2 N (Factor: 1.05) NaOH. In the main trials, 6.3 ml - 6.5 ml - 6.9 ml, respectively, 0.1 ml base was used in the analysis without using the sample.For example, how many ppm is its acidity?
An analyst determines the Cl^- content of rain water with ion chromatography. The data for the calibration line in the range 5 to 50 milli equivalents per liter (mEq/L) is shown in the table below. Additionally, a blank sample was analysed 5 times and the following results obtained: 1.1, 0.5, 0.1, 0.9 and 1.2 ppm Ct Calculate the detection limit (DL) for the method with a 98.3% confidence level. Use ALL data and show equations
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