CHз он нас но "CHз H2N CHз НаС .CH 3 + CH нс CHз н н CHз -CH3 Hас 2,4-Bis(a.,a-dimethylbe nzyl) phenol Ligand 6 formaldehyde N,N-dimethylethylenediamine 4.0096 g 0.9 mL 0.66 mL 1H - Ligand 6 12 11 10 9 8 7 5 4 2 ppm 7 1.75 -9.442 7.259 7.240 -7.238 7.228 7.173 CO - 7.163 7.152 7.140 12.23 \68 L 7.134 2.16 7.127 7.119 000 7.078 7.068 7.057 7.046 CO - 7.035 6.691 LO 96 3.362 2.290 2.276 2.04 2.261 2.01 2.108 11.81 2.093 6.19 11.76/ 2.079 1.659 1.637 1.616

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter8: Addition Via Carbocation
Section: Chapter Questions
Problem 6CTQ
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Question

Using the reaction below and using Ligand 6 to determine the HNMR shown below.

Ligand 6 is a symmetrical Ligand.

Label all the H protons.

CHз
он нас
но
"CHз
H2N
CHз
НаС
.CH 3
+
CH
нс
CHз
н
н
CHз
-CH3
Hас
2,4-Bis(a.,a-dimethylbe nzyl)
phenol
Ligand 6
formaldehyde
N,N-dimethylethylenediamine
4.0096 g
0.9 mL
0.66 mL
Transcribed Image Text:CHз он нас но "CHз H2N CHз НаС .CH 3 + CH нс CHз н н CHз -CH3 Hас 2,4-Bis(a.,a-dimethylbe nzyl) phenol Ligand 6 formaldehyde N,N-dimethylethylenediamine 4.0096 g 0.9 mL 0.66 mL
1H - Ligand 6
12
11
10
9
8
7
5
4
2
ppm
7
1.75
-9.442
7.259
7.240
-7.238
7.228
7.173
CO
- 7.163
7.152
7.140
12.23
\68 L
7.134
2.16
7.127
7.119
000
7.078
7.068
7.057
7.046
CO
- 7.035
6.691
LO
96
3.362
2.290
2.276
2.04
2.261
2.01
2.108
11.81
2.093
6.19
11.76/
2.079
1.659
1.637
1.616
Transcribed Image Text:1H - Ligand 6 12 11 10 9 8 7 5 4 2 ppm 7 1.75 -9.442 7.259 7.240 -7.238 7.228 7.173 CO - 7.163 7.152 7.140 12.23 \68 L 7.134 2.16 7.127 7.119 000 7.078 7.068 7.057 7.046 CO - 7.035 6.691 LO 96 3.362 2.290 2.276 2.04 2.261 2.01 2.108 11.81 2.093 6.19 11.76/ 2.079 1.659 1.637 1.616
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