Compute for the actual moles of acetic anhydride and 1-pentanol used in the experiment using the following data: Acetic anhydride: 29 mL , sp.gr. 0.811g/mL and MW. 102.09 g/mol 1-Pentanol: 26 mL , sp.gr. 0.916g/mL and MW. 88.15 g/mol Which reactant is in excess? Why it needs to have more excess reactants to drive the reaction forward?
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Compute for the actual moles of acetic anhydride and 1-pentanol used in the experiment using the following data:
Acetic anhydride: 29 mL , sp.gr. 0.811g/mL and MW. 102.09 g/mol
1-Pentanol: 26 mL , sp.gr. 0.916g/mL and MW. 88.15 g/mol
Which reactant is in excess? Why it needs to have more excess reactants to drive the reaction forward?
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- In relation to this question: Compute for the actual moles of acetic anhydride and 1-pentanol used in the experiment using the following data: Acetic anhydride: 29 mL , sp.gr. 0.811g/mL and MW. 102.09 g/mol 1-Pentanol: 26 mL , sp.gr. 0.916g/mL and MW. 88.15 g/mol Which reactant is in excess? Why it needs to have more excess reactants to drive the reaction forward? Why is the use of ice bath in the experiment necessary?Hi, can you check my math? Can percent error be negative, if so what does that mean and how do I explain that for my results? These are calculations for Determining the ksp of Calcium Hydroxide Lab. Thanks!how would u justify this question? my answer is correct i just do not understand the justification. this is a non graded practice worksheet
- In this experiment, the problem is that the volume of the volumetric pipet is not accurately known (only 2 sig figs), so any density calculation will also be limited to 2 sig figs. Calibration increases the number of sig figs from 2 to 4. As a result, the density also increases from 2 to 4 sig figs. Explain how and why this is possible.Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466DATA Note: Use the videos as references except when data is provided here. Table 1. Selection of Recrystallizing Solvent. Solvents Dissolution at room temperature? (+ or −) Dissolution at elevated temperature? (+ or −) Distilled water - - Acetone + n/a 95% ethanol - + Toluene + n/a Solid sample: Naphthalene Table 2. Mass Measurements. Mass, g Sample solid 0.5021 Empty watch glass 35.7602 Watch glass with recrystallized sample 36.2485 Table 3. Melting Point Determination. Temperature, oC Appearance of Sample in Capillary Tube … Solid 78.4 Solid 79.3 Solid with signs of liquid 79.9 Solid, liquid 80.6 Liquid, solid 81.3 Liquid with signs of solid … Liquid Theoretical Melting Point, oC: 80.2°C (176.4°F) QUESTIONS Which solvent should be used as the recrystallizing solvent? Check if your chosen solvent satisfies all characteristics of a good…
- In the standardization of HCl against pure anhydrous Na2CO3, 1mL was found to be equivalent to 0.05g of the primary standard. Compute for the normality.please help this is my 4th time posting this and i havent gotten a correct answer. Please actually draw the graph out. A newly discovered enzyme, MBCase, cleaves carbon-carbon bonds of vicinal alcohol; The kinetic parameters were measured for 1.0 nM Of MBGase and determined to be a Km = 10 nM and a kcat = 100 s-1 a.) Sketch the graph out as a double-reciprocal plot (Lineweaver-Burke Plot) and label: -the axes (with units) -the point on the curve that can be used to determine Km -the point on the curve that can be used to determine VmaxThere's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
- There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…Can it please be explain just like in the uploadState and explain one possible source of random error whilst using a pipette.Your answer should justify why this is a random error.